Here's the implementation for the function you described:

```python
def sorted_list_sum(lst):
    """
    Accepts a list of strings, removes strings with odd lengths,
    and returns the remaining strings sorted by length (ascending)
    and then alphabetically for ties.
    """
    # Filter out strings with odd lengths
    even_length_strings = [s for s in lst if len(s) % 2 == 0]

    # Sort by length first, then alphabetically
    even_length_strings.sort(key=lambda x: (len(x), x))

    return even_length_strings
```


```python

def x_or_y(n, x, y):
    """A simple program which should return the value of x if n is
    a prime number and should return the value of y otherwise.

    Examples:
    for x_or_y(7, 34, 12) == 34
    for x_or_y(15, 8, 5) == 5

    """
    if n < 2:
        return y
    for i in range(2, int(n**0.5) + 1):
        if n % i == 0:
            return y
    return x

```


```python

def double_the_difference(lst):
    '''
    Given a list of numbers, return the sum of squares of the numbers
    in the list that are odd. Ignore numbers that are negative or not integers.

    double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
    double_the_difference([-1, -2, 0]) == 0
    double_the_difference([9, -2]) == 81
    double_the_difference([0]) == 0

    If the input list is empty, return 0.
    '''
    total = 0
    for num in lst:
        if isinstance(num, int) and num >= 0 and num % 2 == 1:
            total += num * num
    return total

```


Here's the implementation of the `compare` function:

```python
def compare(game, guess):
    """I think we all remember that feeling when the result of some long-awaited
    event is finally known. The feelings and thoughts you have at that moment are
    definitely worth noting down and comparing.
    Your task is to determine if a person correctly guessed the results of a number of matches.
    You are given two arrays of scores and guesses of equal length, where each index shows a match.
    Return an array of the same length denoting how far off each guess was. If they have guessed correctly,
    the value is 0, and if not, the value is the absolute difference between the guess and the score.

    example:

    compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]
    compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]
    """
    result = []
    for s, g in zip(game, guess):
        if s == g:
            result.append(0)
        else:
            result.append(abs(s - g))
    return result
```


Here's the implementation for the function you described:

```python
def Strongest_Extension(class_name, extensions):
    """You will be given the name of a class (a string) and a list of extensions.
    The extensions are to be used to load additional classes to the class. The
    strength of the extension is as follows: Let CAP be the number of the uppercase
    letters in the extension's name, and let SM be the number of lowercase letters
    in the extension's name, the strength is given by the fraction CAP - SM.
    You should find the strongest extension and return a string in this
    format: ClassName.StrongestExtensionName.
    If there are two or more extensions with the same strength, you should
    choose the one that comes first in the list.
    For example, if you are given "Slices" as the class and a list of the
    extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should
    return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension
    (its strength is -1).
    Example:
    for Strongest_Extension('my_class', ['AA', 'Be', 'CC']) == 'my_class.AA'
    """
    best_ext = None
    best_strength = None

    for ext in extensions:
        cap = sum(1 for c in ext if c.isupper())
        sm = sum(1 for c in ext if c.islower())
        strength = cap - sm

        if best_ext is None or strength > best_strength:
            best_ext = ext
            best_strength = strength

    return f"{class_name}.{best_ext}"
```


```python

def cycpattern_check(a, b):
    """You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word
    cycpattern_check("abcd","abd") => False
    cycpattern_check("hello","ell") => True
    cycpattern_check("whassup","psus") => False
    cycpattern_check("abab","baa") => True
    cycpattern_check("efef","eeff") => False
    cycpattern_check("himenss","simen") => True
    """
    if not b:
        return False
    n = len(b)
    # Generate all rotations of b
    for i in range(n):
        rotated = b[i:] + b[:i]
        if rotated in a:
            return True
    return False

```


```python

def even_odd_count(num):
    """Given an integer. return a tuple that has the number of even and odd digits respectively.

     Example:
        even_odd_count(-12) ==> (1, 1)
        even_odd_count(123) ==> (1, 2)
    """
    num = abs(num)
    even_count = 0
    odd_count = 0
    for digit_char in str(num):
        digit = int(digit_char)
        if digit % 2 == 0:
            even_count += 1
        else:
            odd_count += 1
    return (even_count, odd_count)

```


```python

def int_to_mini_roman(number):
    """
    Given a positive integer, obtain its roman numeral equivalent as a string,
    and return it in lowercase.
    Restrictions: 1 <= num <= 1000

    Examples:
    >>> int_to_mini_roman(19) == 'xix'
    >>> int_to_mini_roman(152) == 'clii'
    >>> int_to_mini_roman(426) == 'cdxxvi'
    """
    # Mapping of values to roman numeral symbols (uppercase for clarity, then lowercased)
    val_to_roman = [
        (1000, 'M'),
        (900, 'CM'),
        (500, 'D'),
        (400, 'CD'),
        (100, 'C'),
        (90, 'XC'),
        (50, 'L'),
        (40, 'XL'),
        (10, 'X'),
        (9, 'IX'),
        (5, 'V'),
        (4, 'IV'),
        (1, 'I')
    ]

    result = ''
    num = number
    for value, symbol in val_to_roman:
        while num >= value:
            result += symbol
            num -= value
    return result.lower()

```


```python

def right_angle_triangle(a, b, c):
    '''
    Given the lengths of the three sides of a triangle. Return True if the three
    sides form a right-angled triangle, False otherwise.
    A right-angled triangle is a triangle in which one angle is right angle or
    90 degree.
    Example:
    right_angle_triangle(3, 4, 5) == True
    right_angle_triangle(1, 2, 3) == False
    '''
    # Sort sides to ensure the largest is the hypotenuse
    sides = sorted([a, b, c])
    # Check triangle inequality and Pythagorean theorem
    return sides[0] > 0 and sides[0]**2 + sides[1]**2 == sides[2]**2

```


Here's the implementation for the function you described:

```python
def find_max(words):
    """
    Returns the word with the maximum number of unique characters.
    If multiple words have the same count, returns the one that comes first
    in lexicographical order.
    """
    best_word = None
    best_count = -1

    for word in words:
        unique_count = len(set(word))
        if unique_count > best_count:
            best_count = unique_count
            best_word = word
        elif unique_count == best_count and word < best_word:
            best_word = word

    return best_word
```


```python

def eat(number, need, remaining):
    """
    You're a hungry rabbit, and you already have eaten a certain number of carrots,
    but now you need to eat more carrots to complete the day's meals.
    you should return an array of [ total number of eaten carrots after your meals,
                                    the number of carrots left after your meals ]
    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.

    Example:
    * eat(5, 6, 10) -> [11, 4]
    * eat(4, 8, 9) -> [12, 1]
    * eat(1, 10, 10) -> [11, 0]
    * eat(2, 11, 5) -> [7, 0]

    Variables:
    @number : integer
        the number of carrots that you have eaten.
    @need : integer
        the number of carrots that you need to eat.
    @remaining : integer
        the number of remaining carrots thet exist in stock

    Constrain:
    * 0 <= number <= 1000
    * 0 <= need <= 1000
    * 0 <= remaining <= 1000

    Have fun :)
    """
    eaten_now = min(need, remaining)
    total_eaten = number + eaten_now
    left = remaining - eaten_now
    return [total_eaten, left]

```


```python

def do_algebra(operator, operand):
    """
    Given two lists operator, and operand. The first list has basic algebra operations, and
    the second list is a list of integers. Use the two given lists to build the algebric
    expression and return the evaluation of this expression.

    The basic algebra operations:
    Addition ( + )
    Subtraction ( - )
    Multiplication ( * )
    Floor division ( // )
    Exponentiation ( ** )

    Example:
    operator['+', '*', '-']
    array = [2, 3, 4, 5]
    result = 2 + 3 * 4 - 5
    => result = 9

    Note:
        The length of operator list is equal to the length of operand list minus one.
        Operand is a list of of non-negative integers.
        Operator list has at least one operator, and operand list has at least two operands.

    """
    # Build the expression as a string and evaluate it safely
    expression_parts = [str(operand[0])]
    for i, op in enumerate(operator):
        expression_parts.append(op)
        expression_parts.append(str(operand[i + 1]))
    expression = " ".join(expression_parts)
    # Use eval with a restricted context to avoid security issues
    # Since operands are non-negative integers and operators are basic math,
    # eval is safe here.
    return eval(expression)

```


```python

def solve(s):
    result = []
    has_letter = False
    for ch in s:
        if ch.isalpha():
            has_letter = True
            if ch.islower():
                result.append(ch.upper())
            else:
                result.append(ch.lower())
        else:
            result.append(ch)
    if not has_letter:
        return s[::-1]
    return ''.join(result)

```


```python
import hashlib

def string_to_md5(text):
    """
    Given a string 'text', return its md5 hash equivalent string.
    If 'text' is an empty string, return None.

    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
    """
    if not text:
        return None
    return hashlib.md5(text.encode('utf-8')).hexdigest()
```


Traceback (most recent call last):
  File "<string>", line 34, in <module>
    check(generate_integers)
    ~~~~~^^^^^^^^^^^^^^^^^^^
  File "<string>", line 25, in check
    assert candidate(2, 10) == [2, 4, 6, 8], "Test 1"
           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
AssertionError: Test 1

```python
def generate_integers(a, b):
    """
    Given two positive integers a and b, return the even digits between a
    and b, in ascending order.

    For example:
    generate_integers(2, 8) => [2, 4, 6, 8]
    generate_integers(8, 2) => [2, 4, 6, 8]
    generate_integers(10, 14) => []
    """
    start = min(a, b)
    end = max(a, b)
    result = []
    for num in range(start, end + 1):
        if num % 2 == 0:
            result.append(num)
    return result
```