{"id": "HumanEval/0", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 171, "completion_tokens": 189, "total_tokens": 360, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 171}}, "wall_s": 11.03, "content": "```python\nfrom typing import List\n\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n    \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n    given threshold.\n    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n    False\n    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n    True\n    \"\"\"\n    # Sort the list to compare adjacent elements\n    sorted_numbers = sorted(numbers)\n    \n    # Check each adjacent pair\n    for i in range(len(sorted_numbers) - 1):\n        if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n            return True\n    \n    return False\n```"}
{"id": "HumanEval/1", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 164, "completion_tokens": 228, "total_tokens": 392, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 164}}, "wall_s": 11.5, "content": "```python\nfrom typing import List\n\ndef separate_paren_groups(paren_string: str) -> List[str]:\n    \"\"\" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to\n    separate those group into separate strings and return the list of those.\n    Separate groups are balanced (each open brace is properly closed) and not nested within each other\n    Ignore any spaces in the input string.\n    >>> separate_paren_groups('( ) (( )) (( )( ))')\n    ['()', '(())', '(()())']\n    \"\"\"\n    # Remove all spaces from the input\n    cleaned = paren_string.replace(' ', '')\n    \n    result = []\n    current_group = \"\"\n    balance = 0\n    \n    for ch in cleaned:\n        current_group += ch\n        if ch == '(':\n            balance += 1\n        elif ch == ')':\n            balance -= 1\n        \n        # When balance reaches 0, we have a complete balanced group\n        if balance == 0:\n            result.append(current_group)\n            current_group = \"\"\n    \n    return result\n```"}
{"id": "HumanEval/2", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 128, "completion_tokens": 90, "total_tokens": 218, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 128}}, "wall_s": 5.26, "content": "```python\n\ndef truncate_number(number: float) -> float:\n    \"\"\" Given a positive floating point number, it can be decomposed into\n    and integer part (largest integer smaller than given number) and decimals\n    (leftover part always smaller than 1).\n\n    Return the decimal part of the number.\n    >>> truncate_number(3.5)\n    0.5\n    \"\"\"\n    return number - int(number)\n\n```"}
{"id": "HumanEval/3", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 162, "completion_tokens": 54, "total_tokens": 216, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 162}}, "wall_s": 3.99, "content": "\n```python\n\nfrom typing import List\n\ndef below_zero(operations: List[int]) -> bool:\n    balance = 0\n    for op in operations:\n        balance += op\n        if balance < 0:\n            return True\n    return False\n\n```"}
{"id": "HumanEval/4", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 160, "completion_tokens": 162, "total_tokens": 322, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 160}}, "wall_s": 8.62, "content": "```python\nfrom typing import List\n\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n    \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n    around the mean of this dataset.\n    Mean Absolute Deviation is the average absolute difference between each\n    element and a centerpoint (mean in this case):\n    MAD = average | x - x_mean |\n    >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n    1.0\n    \"\"\"\n    if not numbers:\n        return 0.0\n    mean = sum(numbers) / len(numbers)\n    deviations = [abs(x - mean) for x in numbers]\n    return sum(deviations) / len(numbers)\n```"}
{"id": "HumanEval/5", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 139, "completion_tokens": 143, "total_tokens": 282, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 139}}, "wall_s": 7.95, "content": "```python\nfrom typing import List\n\ndef intersperse(numbers: List[int], delimeter: int) -> List[int]:\n    \"\"\" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'\n    >>> intersperse([], 4)\n    []\n    >>> intersperse([1, 2, 3], 4)\n    [1, 4, 2, 4, 3]\n    \"\"\"\n    if not numbers:\n        return []\n    \n    result = []\n    for i, num in enumerate(numbers):\n        result.append(num)\n        if i < len(numbers) - 1:\n            result.append(delimeter)\n    return result\n```"}
{"id": "HumanEval/6", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 159, "completion_tokens": 200, "total_tokens": 359, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 159}}, "wall_s": 10.73, "content": "```python\nfrom typing import List\n\ndef parse_nested_parens(paren_string: str) -> List[int]:\n    \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n    For each of the group, output the deepest level of nesting of parentheses.\n    E.g. (()()) has maximum two levels of nesting while ((())) has three.\n\n    >>> parse_nested_parens('(()()) ((())) () ((())()())')\n    [2, 3, 1, 3]\n    \"\"\"\n    groups = paren_string.split()\n    result = []\n    \n    for group in groups:\n        max_depth = 0\n        current_depth = 0\n        \n        for char in group:\n            if char == '(':\n                current_depth += 1\n                max_depth = max(max_depth, current_depth)\n            elif char == ')':\n                current_depth -= 1\n        \n        result.append(max_depth)\n    \n    return result\n```"}
{"id": "HumanEval/7", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 138, "completion_tokens": 106, "total_tokens": 244, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 138}}, "wall_s": 6.35, "content": "```python\nfrom typing import List\n\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n    \"\"\" Filter an input list of strings only for ones that contain given substring\n    >>> filter_by_substring([], 'a')\n    []\n    >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')\n    ['abc', 'bacd', 'array']\n    \"\"\"\n    return [s for s in strings if substring in s]\n```"}
{"id": "HumanEval/8", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 154, "completion_tokens": 151, "total_tokens": 305, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 154}}, "wall_s": 8.55, "content": "\n```python\nfrom typing import List, Tuple\n\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n    \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n    Empty sum should be equal to 0 and empty product should be equal to 1.\n    >>> sum_product([])\n    (0, 1)\n    >>> sum_product([1, 2, 3, 4])\n    (10, 24)\n    \"\"\"\n    total_sum = 0\n    total_product = 1\n    for num in numbers:\n        total_sum += num\n        total_product *= num\n    return (total_sum, total_product)\n```"}
{"id": "HumanEval/9", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 143, "completion_tokens": 62, "total_tokens": 205, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 143}}, "wall_s": 4.26, "content": "```python\nfrom typing import List\n\ndef rolling_max(numbers: List[int]) -> List[int]:\n    result = []\n    current_max = float('-inf')\n    for num in numbers:\n        if num > current_max:\n            current_max = num\n        result.append(current_max)\n    return result\n```"}
{"id": "HumanEval/10", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 189, "completion_tokens": 257, "total_tokens": 446, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 189}}, "wall_s": 13.35, "content": "\n```python\n\ndef is_palindrome(string: str) -> bool:\n    \"\"\" Test if given string is a palindrome \"\"\"\n    return string == string[::-1]\n\n\ndef make_palindrome(string: str) -> str:\n    \"\"\" Find the shortest palindrome that begins with a supplied string.\n    Algorithm idea is simple:\n    - Find the longest postfix of supplied string that is a palindrome.\n    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n    >>> make_palindrome('')\n    ''\n    >>> make_palindrome('cat')\n    'catac'\n    >>> make_palindrome('cata')\n    'catac'\n    \"\"\"\n    if not string:\n        return \"\"\n    \n    # Find the longest palindromic suffix\n    for i in range(len(string), 0, -1):\n        suffix = string[-i:]\n        if is_palindrome(suffix):\n            # The prefix before the palindromic suffix\n            prefix = string[:-i]\n            # Append the reverse of the prefix to make the whole string a palindrome\n            return string + prefix[::-1]\n    \n    # Should never reach here because at least the last character is a palindrome\n    return string\n\n```"}
{"id": "HumanEval/11", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 121, "completion_tokens": 118, "total_tokens": 239, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 121}}, "wall_s": 6.87, "content": "```python\nfrom typing import List\n\ndef string_xor(a: str, b: str) -> str:\n    \"\"\" Input are two strings a and b consisting only of 1s and 0s.\n    Perform binary XOR on these inputs and return result also as a string.\n    >>> string_xor('010', '110')\n    '100'\n    \"\"\"\n    result = []\n    for i in range(len(a)):\n        if a[i] == b[i]:\n            result.append('0')\n        else:\n            result.append('1')\n    return ''.join(result)\n```"}
{"id": "HumanEval/12", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 146, "completion_tokens": 149, "total_tokens": 295, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 146}}, "wall_s": 8.51, "content": "```python\n\nfrom typing import List, Optional\n\ndef longest(strings: List[str]) -> Optional[str]:\n    \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n    strings of the same length. Return None in case the input list is empty.\n    >>> longest([])\n\n    >>> longest(['a', 'b', 'c'])\n    'a'\n    >>> longest(['a', 'bb', 'ccc'])\n    'ccc'\n    \"\"\"\n    if not strings:\n        return None\n    longest_str = strings[0]\n    for s in strings[1:]:\n        if len(s) > len(longest_str):\n            longest_str = s\n    return longest_str\n\n```"}
{"id": "HumanEval/13", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 114, "completion_tokens": 99, "total_tokens": 213, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 114}}, "wall_s": 5.75, "content": "```python\n\ndef greatest_common_divisor(a: int, b: int) -> int:\n    \"\"\" Return a greatest common divisor of two integers a and b\n    >>> greatest_common_divisor(3, 5)\n    1\n    >>> greatest_common_divisor(25, 15)\n    5\n    \"\"\"\n    a, b = abs(a), abs(b)\n    while b:\n        a, b = b, a % b\n    return a\n\n```"}
{"id": "HumanEval/14", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 102, "completion_tokens": 78, "total_tokens": 180, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 102}}, "wall_s": 4.85, "content": "```python\nfrom typing import List\n\ndef all_prefixes(string: str) -> List[str]:\n    \"\"\" Return list of all prefixes from shortest to longest of the input string\n    >>> all_prefixes('abc')\n    ['a', 'ab', 'abc']\n    \"\"\"\n    return [string[:i] for i in range(1, len(string) + 1)]\n```"}
{"id": "HumanEval/15", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 115, "completion_tokens": 87, "total_tokens": 202, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 115}}, "wall_s": 5.13, "content": "```python\n\ndef string_sequence(n: int) -> str:\n    \"\"\" Return a string containing space-delimited numbers starting from 0 upto n inclusive.\n    >>> string_sequence(0)\n    '0'\n    >>> string_sequence(5)\n    '0 1 2 3 4 5'\n    \"\"\"\n    return ' '.join(str(i) for i in range(n + 1))\n\n```"}
{"id": "HumanEval/16", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 115, "completion_tokens": 78, "total_tokens": 193, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 115}}, "wall_s": 4.82, "content": "```python\n\ndef count_distinct_characters(string: str) -> int:\n    \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n    >>> count_distinct_characters('xyzXYZ')\n    3\n    >>> count_distinct_characters('Jerry')\n    4\n    \"\"\"\n    return len(set(string.lower()))\n\n```"}
{"id": "HumanEval/17", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 217, "completion_tokens": 97, "total_tokens": 314, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 217}}, "wall_s": 6.15, "content": "Here's the implementation for the `parse_music` function:\n\n```python\nfrom typing import List\n\ndef parse_music(music_string: str) -> List[int]:\n    notes = music_string.split()\n    result = []\n    for note in notes:\n        if note == 'o':\n            result.append(4)\n        elif note == 'o|':\n            result.append(2)\n        elif note == '.|':\n            result.append(1)\n    return result\n```"}
{"id": "HumanEval/18", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 137, "completion_tokens": 156, "total_tokens": 293, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 137}}, "wall_s": 8.47, "content": "```python\n\ndef how_many_times(string: str, substring: str) -> int:\n    \"\"\" Find how many times a given substring can be found in the original string. Count overlaping cases.\n    >>> how_many_times('', 'a')\n    0\n    >>> how_many_times('aaa', 'a')\n    3\n    >>> how_many_times('aaaa', 'aa')\n    3\n    \"\"\"\n    if not substring:\n        return 0\n    count = 0\n    start = 0\n    while True:\n        pos = string.find(substring, start)\n        if pos == -1:\n            break\n        count += 1\n        start = pos + 1\n    return count\n\n```"}
{"id": "HumanEval/19", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 148, "completion_tokens": 206, "total_tokens": 354, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 148}}, "wall_s": 10.49, "content": "```python\nfrom typing import List\n\ndef sort_numbers(numbers: str) -> str:\n    \"\"\" Input is a space-delimited string of numberals from 'zero' to 'nine'.\n    Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n    Return the string with numbers sorted from smallest to largest\n    >>> sort_numbers('three one five')\n    'one three five'\n    \"\"\"\n    numeral_to_value = {\n        'zero': 0, 'one': 1, 'two': 2, 'three': 3, 'four': 4,\n        'five': 5, 'six': 6, 'seven': 7, 'eight': 8, 'nine': 9\n    }\n    tokens = numbers.split()\n    sorted_tokens = sorted(tokens, key=lambda x: numeral_to_value[x])\n    return ' '.join(sorted_tokens)\n```"}
{"id": "HumanEval/20", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 214, "completion_tokens": 153, "total_tokens": 367, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 214}}, "wall_s": 8.74, "content": "\n```python\n\nfrom typing import List, Tuple\n\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n    # Sort the list to easily compare adjacent elements\n    sorted_numbers = sorted(numbers)\n    \n    # Initialize with a large difference\n    min_diff = float('inf')\n    closest_pair = (0.0, 0.0)\n    \n    # Compare each adjacent pair\n    for i in range(len(sorted_numbers) - 1):\n        a = sorted_numbers[i]\n        b = sorted_numbers[i + 1]\n        diff = b - a\n        if diff < min_diff:\n            min_diff = diff\n            closest_pair = (a, b)\n    \n    return closest_pair\n\n```"}
{"id": "HumanEval/21", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 168, "completion_tokens": 201, "total_tokens": 369, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 168}}, "wall_s": 10.5, "content": "```python\nfrom typing import List\n\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n    \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n    such that the smallest number will become 0 and the largest will become 1\n    >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\n    [0.0, 0.25, 0.5, 0.75, 1.0]\n    \"\"\"\n    min_val = min(numbers)\n    max_val = max(numbers)\n    range_val = max_val - min_val\n    if range_val == 0:\n        # If all numbers are the same, return list of zeros (or handle as needed)\n        return [0.0] * len(numbers)\n    return [(x - min_val) / range_val for x in numbers]\n```"}
{"id": "HumanEval/22", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 138, "completion_tokens": 107, "total_tokens": 245, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 138}}, "wall_s": 6.22, "content": "```python\nfrom typing import List, Any\n\ndef filter_integers(values: List[Any]) -> List[int]:\n    \"\"\" Filter given list of any python values only for integers\n    >>> filter_integers(['a', 3.14, 5])\n    [5]\n    >>> filter_integers([1, 2, 3, 'abc', {}, []])\n    [1, 2, 3]\n    \"\"\"\n    return [v for v in values if isinstance(v, int)]\n```"}
{"id": "HumanEval/23", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 85, "completion_tokens": 45, "total_tokens": 130, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 85}}, "wall_s": 3.06, "content": "```python\n\ndef strlen(string: str) -> int:\n    \"\"\" Return length of given string\n    >>> strlen('')\n    0\n    >>> strlen('abc')\n    3\n    \"\"\"\n    return len(string)\n\n```"}
{"id": "HumanEval/24", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 94, "completion_tokens": 83, "total_tokens": 177, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 94}}, "wall_s": 4.78, "content": "```python\n\ndef largest_divisor(n: int) -> int:\n    \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n    >>> largest_divisor(15)\n    5\n    \"\"\"\n    for d in range(n // 2, 0, -1):\n        if n % d == 0:\n            return d\n    return 1\n\n```"}
{"id": "HumanEval/25", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 168, "completion_tokens": 183, "total_tokens": 351, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 168}}, "wall_s": 9.68, "content": "```python\n\nfrom typing import List\n\ndef factorize(n: int) -> List[int]:\n    \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n    Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.\n    Input number should be equal to the product of all factors\n    >>> factorize(8)\n    [2, 2, 2]\n    >>> factorize(25)\n    [5, 5]\n    >>> factorize(70)\n    [2, 5, 7]\n    \"\"\"\n    factors = []\n    d = 2\n    while d * d <= n:\n        while n % d == 0:\n            factors.append(d)\n            n //= d\n        d += 1\n    if n > 1:\n        factors.append(n)\n    return factors\n\n```"}
{"id": "HumanEval/26", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 131, "completion_tokens": 159, "total_tokens": 290, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 131}}, "wall_s": 8.37, "content": "```python\nfrom typing import List\n\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n    \"\"\" From a list of integers, remove all elements that occur more than once.\n    Keep order of elements left the same as in the input.\n    >>> remove_duplicates([1, 2, 3, 2, 4])\n    [1, 3, 4]\n    \"\"\"\n    # Count occurrences of each number\n    counts = {}\n    for num in numbers:\n        counts[num] = counts.get(num, 0) + 1\n    \n    # Keep only numbers that appear exactly once\n    result = []\n    for num in numbers:\n        if counts[num] == 1:\n            result.append(num)\n    \n    return result\n```"}
{"id": "HumanEval/27", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 91, "completion_tokens": 54, "total_tokens": 145, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 91}}, "wall_s": 3.46, "content": "\n```python\n\ndef flip_case(string: str) -> str:\n    \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n    >>> flip_case('Hello')\n    'hELLO'\n    \"\"\"\n    return string.swapcase()\n\n```"}
{"id": "HumanEval/28", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 106, "completion_tokens": 69, "total_tokens": 175, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 106}}, "wall_s": 4.22, "content": "\n```python\nfrom typing import List\n\ndef concatenate(strings: List[str]) -> str:\n    \"\"\" Concatenate list of strings into a single string\n    >>> concatenate([])\n    ''\n    >>> concatenate(['a', 'b', 'c'])\n    'abc'\n    \"\"\"\n    return ''.join(strings)\n```"}
{"id": "HumanEval/29", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 133, "completion_tokens": 104, "total_tokens": 237, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 133}}, "wall_s": 5.96, "content": "\n```python\nfrom typing import List\n\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n    \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n    >>> filter_by_prefix([], 'a')\n    []\n    >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')\n    ['abc', 'array']\n    \"\"\"\n    return [s for s in strings if s.startswith(prefix)]\n```"}
{"id": "HumanEval/30", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 160, "completion_tokens": 129, "total_tokens": 289, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 160}}, "wall_s": 7.37, "content": "```python\n\ndef get_positive(l: list):\n    \"\"\"Return only positive numbers in the list.\n    >>> get_positive([-1, 2, -4, 5, 6])\n    [2, 5, 6]\n    >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    [5, 3, 2, 3, 9, 123, 1]\n    \"\"\"\n    return [x for x in l if x > 0]\n\n```"}
{"id": "HumanEval/31", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 142, "completion_tokens": 191, "total_tokens": 333, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 142}}, "wall_s": 10.06, "content": "\n```python\n\ndef is_prime(n):\n    \"\"\"Return true if a given number is prime, and false otherwise.\n    >>> is_prime(6)\n    False\n    >>> is_prime(101)\n    True\n    >>> is_prime(11)\n    True\n    >>> is_prime(13441)\n    True\n    >>> is_prime(61)\n    True\n    >>> is_prime(4)\n    False\n    >>> is_prime(1)\n    False\n    \"\"\"\n    if n <= 1:\n        return False\n    if n <= 3:\n        return True\n    if n % 2 == 0 or n % 3 == 0:\n        return False\n    i = 5\n    while i * i <= n:\n        if n % i == 0 or n % (i + 2) == 0:\n            return False\n        i += 6\n    return True\n\n```"}
{"id": "HumanEval/32", "passed": false, "detail": "Traceback (most recent call last):\n  File \"<string>\", line 76, in <module>\n    check(find_zero)\n    ~~~~~^^^^^^^^^^^\n  File \"<string>\", line 73, in check\n    assert math.fabs(poly(coeffs, solution)) < 1e-4\n           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^\nAssertionError", "finish_reason": "stop", "usage": {"prompt_tokens": 307, "completion_tokens": 532, "total_tokens": 839, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 307}}, "wall_s": 26.05, "content": "Here's the implementation for the `find_zero` function using the bisection method, assuming the polynomial has an even number of coefficients and a nonzero leading coefficient:\n\n```python\nimport math\n\ndef poly(xs: list, x: float):\n    \"\"\"\n    Evaluates polynomial with coefficients xs at point x.\n    return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n\n    \"\"\"\n    return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])\n\ndef find_zero(xs: list):\n    \"\"\" xs are coefficients of a polynomial.\n    find_zero find x such that poly(x) = 0.\n    find_zero returns only only zero point, even if there are many.\n    Moreover, find_zero only takes list xs having even number of coefficients\n    and largest non zero coefficient as it guarantees\n    a solution.\n    >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x\n    -0.5\n    >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3\n    1.0\n    \"\"\"\n    # Find a starting interval where poly changes sign\n    # Use a simple search: start from 0 and expand outward\n    low = 0.0\n    high = 1.0\n    f_low = poly(xs, low)\n    f_high = poly(xs, high)\n\n    # Expand until we find a sign change\n    while f_low * f_high > 0:\n        low -= 1.0\n        high += 1.0\n        f_low = poly(xs, low)\n        f_high = poly(xs, high)\n\n    # Bisection method\n    for _ in range(50):  # enough iterations for high precision\n        mid = (low + high) / 2\n        f_mid = poly(xs, mid)\n        if f_mid == 0:\n            return mid\n        if f_low * f_mid < 0:\n            high = mid\n            f_high = f_mid\n        else:\n            low = mid\n            f_low = f_mid\n\n    return (low + high) / 2\n```"}
{"id": "HumanEval/33", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 196, "completion_tokens": 271, "total_tokens": 467, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 196}}, "wall_s": 13.72, "content": "Here's the implementation for the function you described:\n\n```python\ndef sort_third(l: list):\n    \"\"\"This function takes a list l and returns a list l' such that\n    l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n    to the values of the corresponding indices of l, but sorted.\n    >>> sort_third([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n    [2, 6, 3, 4, 8, 9, 5]\n    \"\"\"\n    # Extract values at indices divisible by 3\n    divisible_values = [l[i] for i in range(len(l)) if i % 3 == 0]\n    # Sort them\n    divisible_values.sort()\n    \n    # Build result list\n    result = []\n    sorted_index = 0\n    for i in range(len(l)):\n        if i % 3 == 0:\n            result.append(divisible_values[sorted_index])\n            sorted_index += 1\n        else:\n            result.append(l[i])\n    \n    return result\n```"}
{"id": "HumanEval/34", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 116, "completion_tokens": 77, "total_tokens": 193, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 116}}, "wall_s": 4.67, "content": "```python\n\ndef unique(l: list):\n    \"\"\"Return sorted unique elements in a list\n    >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [0, 2, 3, 5, 9, 123]\n    \"\"\"\n    return sorted(set(l))\n\n```"}
{"id": "HumanEval/35", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 123, "completion_tokens": 131, "total_tokens": 254, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 123}}, "wall_s": 7.05, "content": "```python\n\ndef max_element(l: list):\n    \"\"\"Return maximum element in the list.\n    >>> max_element([1, 2, 3])\n    3\n    >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])\n    123\n    \"\"\"\n    if not l:\n        raise ValueError(\"max_element() arg is an empty list\")\n    max_val = l[0]\n    for x in l[1:]:\n        if x > max_val:\n            max_val = x\n    return max_val\n\n```"}
{"id": "HumanEval/36", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 123, "completion_tokens": 131, "total_tokens": 254, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 123}}, "wall_s": 7.05, "content": "Here's the implementation for the function:\n\n```python\ndef fizz_buzz(n: int):\n    \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n    >>> fizz_buzz(50)\n    0\n    >>> fizz_buzz(78)\n    2\n    >>> fizz_buzz(79)\n    3\n    \"\"\"\n    count = 0\n    for i in range(n):\n        if i % 11 == 0 or i % 13 == 0:\n            count += str(i).count('7')\n    return count\n```"}
{"id": "HumanEval/37", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 169, "completion_tokens": 206, "total_tokens": 375, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 169}}, "wall_s": 10.54, "content": "\n```python\n\ndef sort_even(l: list):\n    \"\"\"This function takes a list l and returns a list l' such that\n    l' is identical to l in the odd indicies, while its values at the even indicies are equal\n    to the values of the even indicies of l, but sorted.\n    >>> sort_even([1, 2, 3])\n    [1, 2, 3]\n    >>> sort_even([5, 6, 3, 4])\n    [3, 6, 5, 4]\n    \"\"\"\n    even_values = sorted([l[i] for i in range(0, len(l), 2)])\n    result = []\n    even_idx = 0\n    for i in range(len(l)):\n        if i % 2 == 0:\n            result.append(even_values[even_idx])\n            even_idx += 1\n        else:\n            result.append(l[i])\n    return result\n\n```"}
{"id": "HumanEval/38", "passed": false, "detail": "Traceback (most recent call last):\n  File \"<string>\", line 30, in <module>\n    check(decode_cyclic)\n    ~~~~~^^^^^^^^^^^^^^^\n  File \"<string>\", line 26, in check\n    encoded_str = encode_cyclic(str)\n                  ^^^^^^^^^^^^^\nNameError: name 'encode_cyclic' is not defined. Did you mean: 'decode_cyclic'?", "finish_reason": "stop", "usage": {"prompt_tokens": 204, "completion_tokens": 135, "total_tokens": 339, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 204}}, "wall_s": 7.61, "content": "\n```python\n\ndef decode_cyclic(s: str):\n    \"\"\"\n    takes as input string encoded with encode_cyclic function. Returns decoded string.\n    \"\"\"\n    # split string into groups of three characters\n    groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]\n    # reverse the cycle: move last character to front for groups of length 3\n    groups = [(group[-1:] + group[:-1]) if len(group) == 3 else group for group in groups]\n    return \"\".join(groups)\n\n```"}
{"id": "HumanEval/39", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 135, "completion_tokens": 240, "total_tokens": 375, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 135}}, "wall_s": 11.85, "content": "```python\n\ndef prime_fib(n: int):\n    \"\"\"\n    prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n    >>> prime_fib(1)\n    2\n    >>> prime_fib(2)\n    3\n    >>> prime_fib(3)\n    5\n    >>> prime_fib(4)\n    13\n    >>> prime_fib(5)\n    89\n    \"\"\"\n    def is_prime(num: int) -> bool:\n        if num < 2:\n            return False\n        if num == 2:\n            return True\n        if num % 2 == 0:\n            return False\n        i = 3\n        while i * i <= num:\n            if num % i == 0:\n                return False\n            i += 2\n        return True\n\n    count = 0\n    a, b = 1, 1\n    while True:\n        # next Fibonacci number\n        fib = a + b\n        a, b = b, fib\n        if is_prime(fib):\n            count += 1\n            if count == n:\n                return fib\n\n```"}
{"id": "HumanEval/40", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 209, "completion_tokens": 119, "total_tokens": 328, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 209}}, "wall_s": 6.96, "content": "```python\n\ndef triples_sum_to_zero(l: list):\n    \"\"\"\n    triples_sum_to_zero takes a list of integers as an input.\n    it returns True if there are three distinct elements in the list that\n    sum to zero, and False otherwise.\n    \"\"\"\n    n = len(l)\n    for i in range(n):\n        for j in range(i + 1, n):\n            for k in range(j + 1, n):\n                if l[i] + l[j] + l[k] == 0:\n                    return True\n    return False\n\n```"}
{"id": "HumanEval/41", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 197, "completion_tokens": 213, "total_tokens": 410, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 197}}, "wall_s": 11.03, "content": "```python\n\ndef car_race_collision(n: int) -> int:\n    \"\"\"\n    Imagine a road that's a perfectly straight infinitely long line.\n    n cars are driving left to right;  simultaneously, a different set of n cars\n    are driving right to left.   The two sets of cars start out being very far from\n    each other.  All cars move in the same speed.  Two cars are said to collide\n    when a car that's moving left to right hits a car that's moving right to left.\n    However, the cars are infinitely sturdy and strong; as a result, they continue moving\n    in their trajectory as if they did not collide.\n\n    This function outputs the number of such collisions.\n    \"\"\"\n    # Each car from the left-to-right set will eventually meet each car\n    # from the right-to-left set exactly once, because they all move at\n    # the same speed and the road is infinite. So total collisions = n * n.\n    return n * n\n\n```"}
{"id": "HumanEval/42", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 155, "completion_tokens": 122, "total_tokens": 277, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 155}}, "wall_s": 7.08, "content": "```python\n\ndef incr_list(l: list):\n    \"\"\"Return list with elements incremented by 1.\n    >>> incr_list([1, 2, 3])\n    [2, 3, 4]\n    >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])\n    [6, 4, 6, 3, 4, 4, 10, 1, 124]\n    \"\"\"\n    return [x + 1 for x in l]\n\n```"}
{"id": "HumanEval/43", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 200, "completion_tokens": 186, "total_tokens": 386, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 200}}, "wall_s": 10.16, "content": "```python\n\ndef pairs_sum_to_zero(l):\n    \"\"\"\n    pairs_sum_to_zero takes a list of integers as an input.\n    it returns True if there are two distinct elements in the list that\n    sum to zero, and False otherwise.\n    >>> pairs_sum_to_zero([1, 3, 5, 0])\n    False\n    >>> pairs_sum_to_zero([1, 3, -2, 1])\n    False\n    >>> pairs_sum_to_zero([1, 2, 3, 7])\n    False\n    >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])\n    True\n    >>> pairs_sum_to_zero([1])\n    False\n    \"\"\"\n    seen = set()\n    for num in l:\n        if -num in seen:\n            return True\n        seen.add(num)\n    return False\n\n```"}
{"id": "HumanEval/44", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 134, "completion_tokens": 136, "total_tokens": 270, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 134}}, "wall_s": 7.6, "content": "```python\ndef change_base(x: int, base: int):\n    \"\"\"Change numerical base of input number x to base.\n    return string representation after the conversion.\n    base numbers are less than 10.\n    >>> change_base(8, 3)\n    '22'\n    >>> change_base(8, 2)\n    '1000'\n    >>> change_base(7, 2)\n    '111'\n    \"\"\"\n    if x == 0:\n        return '0'\n    \n    digits = []\n    while x > 0:\n        digits.append(str(x % base))\n        x //= base\n    \n    return ''.join(reversed(digits))\n```"}
{"id": "HumanEval/45", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 88, "completion_tokens": 52, "total_tokens": 140, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 88}}, "wall_s": 3.49, "content": "```python\n\ndef triangle_area(a, h):\n    \"\"\"Given length of a side and high return area for a triangle.\n    >>> triangle_area(5, 3)\n    7.5\n    \"\"\"\n    return a * h / 2\n\n```"}
{"id": "HumanEval/46", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 211, "completion_tokens": 310, "total_tokens": 521, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 211}}, "wall_s": 16.01, "content": "Here's the efficient, iterative implementation for the fib4 sequence:\n\n```python\ndef fib4(n: int):\n    \"\"\"The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:\n    fib4(0) -> 0\n    fib4(1) -> 0\n    fib4(2) -> 2\n    fib4(3) -> 0\n    fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n    Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.\n    >>> fib4(5)\n    4\n    >>> fib4(6)\n    8\n    >>> fib4(7)\n    14\n    \"\"\"\n    if n == 0:\n        return 0\n    if n == 1:\n        return 0\n    if n == 2:\n        return 2\n    if n == 3:\n        return 0\n\n    # Initial values for n=0,1,2,3\n    a, b, c, d = 0, 0, 2, 0\n\n    for _ in range(4, n + 1):\n        next_val = a + b + c + d\n        a, b, c, d = b, c, d, next_val\n\n    return d\n```"}
{"id": "HumanEval/47", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 117, "completion_tokens": 155, "total_tokens": 272, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 117}}, "wall_s": 8.41, "content": "Here's the implementation for the `median` function:\n\n```python\ndef median(l: list):\n    \"\"\"Return median of elements in the list l.\n    >>> median([3, 1, 2, 4, 5])\n    3\n    >>> median([-10, 4, 6, 1000, 10, 20])\n    15.0\n    \"\"\"\n    sorted_l = sorted(l)\n    n = len(sorted_l)\n    if n % 2 == 1:\n        return sorted_l[n // 2]\n    else:\n        left = sorted_l[n // 2 - 1]\n        right = sorted_l[n // 2]\n        return (left + right) / 2.0\n```"}
{"id": "HumanEval/48", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 120, "completion_tokens": 101, "total_tokens": 221, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 120}}, "wall_s": 5.97, "content": "```python\ndef is_palindrome(text: str):\n    \"\"\"\n    Checks if given string is a palindrome\n    >>> is_palindrome('')\n    True\n    >>> is_palindrome('aba')\n    True\n    >>> is_palindrome('aaaaa')\n    True\n    >>> is_palindrome('zbcd')\n    False\n    \"\"\"\n    cleaned = ''.join(c.lower() for c in text if c.isalnum())\n    return cleaned == cleaned[::-1]\n```"}
{"id": "HumanEval/49", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 143, "completion_tokens": 210, "total_tokens": 353, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 143}}, "wall_s": 11.05, "content": "Here's the implementation using fast modular exponentiation to handle large values efficiently:\n\n```python\ndef modp(n: int, p: int):\n    \"\"\"Return 2^n modulo p (be aware of numerics).\n    >>> modp(3, 5)\n    3\n    >>> modp(1101, 101)\n    2\n    >>> modp(0, 101)\n    1\n    >>> modp(3, 11)\n    8\n    >>> modp(100, 101)\n    1\n    \"\"\"\n    if p == 0:\n        raise ValueError(\"p must be non-zero\")\n    if n == 0:\n        return 1 % p\n\n    result = 1\n    base = 2 % p\n    exp = n\n\n    while exp > 0:\n        if exp & 1:\n            result = (result * base) % p\n        base = (base * base) % p\n        exp >>= 1\n\n    return result\n```"}
{"id": "HumanEval/50", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 138, "completion_tokens": 127, "total_tokens": 265, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 138}}, "wall_s": 7.22, "content": "\n```python\n\ndef encode_shift(s: str):\n    \"\"\"\n    returns encoded string by shifting every character by 5 in the alphabet.\n    \"\"\"\n    return \"\".join([chr(((ord(ch) + 5 - ord(\"a\")) % 26) + ord(\"a\")) for ch in s])\n\n\ndef decode_shift(s: str):\n    \"\"\"\n    takes as input string encoded with encode_shift function. Returns decoded string.\n    \"\"\"\n    return \"\".join([chr(((ord(ch) - 5 - ord(\"a\")) % 26) + ord(\"a\")) for ch in s])\n\n```"}
{"id": "HumanEval/51", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 159, "completion_tokens": 141, "total_tokens": 300, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 159}}, "wall_s": 7.93, "content": "\n```python\n\ndef remove_vowels(text):\n    \"\"\"\n    remove_vowels is a function that takes string and returns string without vowels.\n    >>> remove_vowels('')\n    ''\n    >>> remove_vowels(\"abcdef\\nghijklm\")\n    'bcdf\\nghjklm'\n    >>> remove_vowels('abcdef')\n    'bcdf'\n    >>> remove_vowels('aaaaa')\n    ''\n    >>> remove_vowels('aaBAA')\n    'B'\n    >>> remove_vowels('zbcd')\n    'zbcd'\n    \"\"\"\n    vowels = set('aeiouAEIOU')\n    return ''.join(ch for ch in text if ch not in vowels)\n\n```"}
{"id": "HumanEval/52", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 125, "completion_tokens": 100, "total_tokens": 225, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 125}}, "wall_s": 5.92, "content": "```python\ndef below_threshold(l: list, t: int):\n    \"\"\"Return True if all numbers in the list l are below threshold t.\n    >>> below_threshold([1, 2, 4, 10], 100)\n    True\n    >>> below_threshold([1, 20, 4, 10], 5)\n    False\n    \"\"\"\n    for num in l:\n        if num >= t:\n            return False\n    return True\n```"}
{"id": "HumanEval/53", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 94, "completion_tokens": 55, "total_tokens": 149, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 94}}, "wall_s": 3.63, "content": "```python\ndef add(x: int, y: int):\n    \"\"\"Add two numbers x and y\n    >>> add(2, 3)\n    5\n    >>> add(5, 7)\n    12\n    \"\"\"\n    return x + y\n```"}
{"id": "HumanEval/54", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 195, "completion_tokens": 176, "total_tokens": 371, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 195}}, "wall_s": 9.75, "content": "```python\n\ndef same_chars(s0: str, s1: str):\n    \"\"\"\n    Check if two words have the same characters.\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n    True\n    >>> same_chars('abcd', 'dddddddabc')\n    True\n    >>> same_chars('dddddddabc', 'abcd')\n    True\n    >>> same_chars('eabcd', 'dddddddabc')\n    False\n    >>> same_chars('abcd', 'dddddddabce')\n    False\n    >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n    False\n    \"\"\"\n    # Remove duplicates by converting to set and compare sorted characters\n    return sorted(set(s0)) == sorted(set(s1))\n\n```"}
{"id": "HumanEval/55", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 92, "completion_tokens": 110, "total_tokens": 202, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 92}}, "wall_s": 6.51, "content": "```python\n\ndef fib(n: int):\n    \"\"\"Return n-th Fibonacci number.\n    >>> fib(10)\n    55\n    >>> fib(1)\n    1\n    >>> fib(8)\n    21\n    \"\"\"\n    if n <= 0:\n        return 0\n    elif n == 1:\n        return 1\n    a, b = 0, 1\n    for _ in range(2, n + 1):\n        a, b = b, a + b\n    return b\n\n```"}
{"id": "HumanEval/56", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 138, "completion_tokens": 148, "total_tokens": 286, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 138}}, "wall_s": 8.59, "content": "```python\ndef correct_bracketing(brackets: str):\n    \"\"\" brackets is a string of \"<\" and \">\".\n    return True if every opening bracket has a corresponding closing bracket.\n\n    >>> correct_bracketing(\"<\")\n    False\n    >>> correct_bracketing(\"<>\")\n    True\n    >>> correct_bracketing(\"<<><>>\")\n    True\n    >>> correct_bracketing(\"><<>\")\n    False\n    \"\"\"\n    count = 0\n    for b in brackets:\n        if b == \"<\":\n            count += 1\n        elif b == \">\":\n            if count == 0:\n                return False\n            count -= 1\n    return count == 0\n```"}
{"id": "HumanEval/57", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 129, "completion_tokens": 140, "total_tokens": 269, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 129}}, "wall_s": 8.18, "content": "```python\n\ndef monotonic(l: list):\n    \"\"\"Return True if list elements are monotonically increasing or decreasing.\"\"\"\n    if len(l) <= 1:\n        return True\n    # Determine direction from first non-equal pair\n    increasing = None\n    for i in range(1, len(l)):\n        if l[i] > l[i-1]:\n            if increasing is None:\n                increasing = True\n            elif not increasing:\n                return False\n        elif l[i] < l[i-1]:\n            if increasing is None:\n                increasing = False\n            elif increasing:\n                return False\n        # if equal, continue without changing direction\n    return True\n\n```"}
{"id": "HumanEval/58", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 157, "completion_tokens": 178, "total_tokens": 335, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 157}}, "wall_s": 10.09, "content": "```python\n\ndef common(l1: list, l2: list):\n    \"\"\"Return sorted unique common elements for two lists.\n    >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n    [1, 5, 653]\n    >>> common([5, 3, 2, 8], [3, 2])\n    [2, 3]\n\n    \"\"\"\n    # Convert both lists to sets to remove duplicates\n    set1 = set(l1)\n    set2 = set(l2)\n    \n    # Find intersection of the two sets\n    common_elements = set1 & set2\n    \n    # Return sorted list of the common elements\n    return sorted(common_elements)\n\n```"}
{"id": "HumanEval/59", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 104, "completion_tokens": 119, "total_tokens": 223, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 104}}, "wall_s": 7.07, "content": "```python\n\ndef largest_prime_factor(n: int):\n    \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n    >>> largest_prime_factor(13195)\n    29\n    >>> largest_prime_factor(2048)\n    2\n    \"\"\"\n    factor = 2\n    while factor * factor <= n:\n        if n % factor == 0:\n            n //= factor\n        else:\n            factor += 1 if factor == 2 else 2  # after 2, check only odd numbers\n    return n\n\n```"}
{"id": "HumanEval/60", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 132, "completion_tokens": 101, "total_tokens": 233, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 132}}, "wall_s": 6.27, "content": "```python\ndef sum_to_n(n: int):\n    \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n    >>> sum_to_n(30)\n    465\n    >>> sum_to_n(100)\n    5050\n    >>> sum_to_n(5)\n    15\n    >>> sum_to_n(10)\n    55\n    >>> sum_to_n(1)\n    1\n    \"\"\"\n    return n * (n + 1) // 2\n```"}
{"id": "HumanEval/61", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 138, "completion_tokens": 147, "total_tokens": 285, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 138}}, "wall_s": 8.63, "content": "```python\ndef correct_bracketing(brackets: str):\n    \"\"\" brackets is a string of \"(\" and \")\".\n    return True if every opening bracket has a corresponding closing bracket.\n\n    >>> correct_bracketing(\"(\")\n    False\n    >>> correct_bracketing(\"()\")\n    True\n    >>> correct_bracketing(\"(()())\")\n    True\n    >>> correct_bracketing(\")(()\")\n    False\n    \"\"\"\n    balance = 0\n    for b in brackets:\n        if b == '(':\n            balance += 1\n        elif b == ')':\n            balance -= 1\n        if balance < 0:\n            return False\n    return balance == 0\n```"}
{"id": "HumanEval/62", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 152, "completion_tokens": 148, "total_tokens": 300, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 152}}, "wall_s": 8.67, "content": "```python\n\ndef derivative(xs: list):\n    \"\"\" xs represent coefficients of a polynomial.\n    xs[0] + xs[1] * x + xs[2] * x^2 + ....\n     Return derivative of this polynomial in the same form.\n    >>> derivative([3, 1, 2, 4, 5])\n    [1, 4, 12, 20]\n    >>> derivative([1, 2, 3])\n    [2, 6]\n    \"\"\"\n    if len(xs) <= 1:\n        return []\n    result = []\n    for i in range(1, len(xs)):\n        result.append(i * xs[i])\n    return result\n\n```"}
{"id": "HumanEval/63", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 188, "completion_tokens": 259, "total_tokens": 447, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 188}}, "wall_s": 14.12, "content": "Here's the efficient implementation using iterative computation with three variables:\n\n```python\ndef fibfib(n: int):\n    \"\"\"The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:\n    fibfib(0) == 0\n    fibfib(1) == 0\n    fibfib(2) == 1\n    fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n    Please write a function to efficiently compute the n-th element of the fibfib number sequence.\n    >>> fibfib(1)\n    0\n    >>> fibfib(5)\n    4\n    >>> fibfib(8)\n    24\n    \"\"\"\n    if n == 0 or n == 1:\n        return 0\n    if n == 2:\n        return 1\n    \n    a, b, c = 0, 0, 1  # representing fibfib(0), fibfib(1), fibfib(2)\n    \n    for _ in range(3, n + 1):\n        next_val = a + b + c\n        a, b, c = b, c, next_val\n    \n    return c\n```"}
{"id": "HumanEval/64", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 167, "completion_tokens": 197, "total_tokens": 364, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 167}}, "wall_s": 11.04, "content": "Here's the implementation for the `vowels_count` function:\n\n```python\ndef vowels_count(s):\n    \"\"\"Write a function vowels_count which takes a string representing\n    a word as input and returns the number of vowels in the string.\n    Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n    vowel, but only when it is at the end of the given word.\n\n    Example:\n    >>> vowels_count(\"abcde\")\n    2\n    >>> vowels_count(\"ACEDY\")\n    3\n    \"\"\"\n    vowels = set('aeiou')\n    count = 0\n    s_lower = s.lower()\n    for i, ch in enumerate(s_lower):\n        if ch in vowels:\n            count += 1\n        elif ch == 'y' and i == len(s) - 1:\n            count += 1\n    return count\n```"}
{"id": "HumanEval/65", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 129, "completion_tokens": 129, "total_tokens": 258, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 129}}, "wall_s": 7.6, "content": "Here's the implementation for the `circular_shift` function:\n\n```python\ndef circular_shift(x, shift):\n    \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n    and return the result as a string.\n    If shift > number of digits, return digits reversed.\n    >>> circular_shift(12, 1)\n    \"21\"\n    >>> circular_shift(12, 2)\n    \"12\"\n    \"\"\"\n    digits = str(x)\n    if shift > len(digits):\n        return digits[::-1]\n    return digits[-shift:] + digits[:-shift]\n```"}
{"id": "HumanEval/66", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 156, "completion_tokens": 145, "total_tokens": 301, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 156}}, "wall_s": 8.37, "content": "\n```python\n\ndef digitSum(s):\n    \"\"\"Task\n    Write a function that takes a string as input and returns the sum of the upper characters only'\n    ASCII codes.\n\n    Examples:\n        digitSum(\"\") => 0\n        digitSum(\"abAB\") => 131\n        digitSum(\"abcCd\") => 67\n        digitSum(\"helloE\") => 69\n        digitSum(\"woArBld\") => 131\n        digitSum(\"aAaaaXa\") => 153\n    \"\"\"\n    total = 0\n    for ch in s:\n        if 'A' <= ch <= 'Z':\n            total += ord(ch)\n    return total\n\n```"}
{"id": "HumanEval/67", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 258, "completion_tokens": 153, "total_tokens": 411, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 258}}, "wall_s": 9.33, "content": "Here's the implementation for the function you described:\n\n```python\nimport re\n\ndef fruit_distribution(s: str, n: int) -> int:\n    \"\"\"\n    Given a string representing the number of apples and oranges and an integer\n    representing the total number of fruits in the basket, returns the number of\n    mango fruits in the basket.\n    \"\"\"\n    # Extract numbers for apples and oranges from the string\n    numbers = list(map(int, re.findall(r'\\d+', s)))\n    \n    # The string should contain exactly two numbers: apples and oranges\n    apples, oranges = numbers[0], numbers[1]\n    \n    # Calculate mango fruits\n    mangoes = n - apples - oranges\n    \n    return mangoes\n```"}
{"id": "HumanEval/68", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 355, "completion_tokens": 239, "total_tokens": 594, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 355}}, "wall_s": 14.06, "content": "Here's the implementation for the `pluck` function:  \n\n```python\ndef pluck(arr):\n    \"\"\"\n    Given an array representing a branch of a tree that has non-negative integer nodes\n    your task is to pluck one of the nodes and return it.\n    The plucked node should be the node with the smallest even value.\n    If multiple nodes with the same smallest even value are found return the node that has smallest index.\n\n    The plucked node should be returned in a list, [ smallest_value, its index ],\n    If there are no even values or the given array is empty, return [].\n    \"\"\"\n    if not arr:\n        return []\n    \n    smallest_even = None\n    smallest_index = None\n    \n    for i, val in enumerate(arr):\n        if val % 2 == 0:\n            if smallest_even is None or val < smallest_even:\n                smallest_even = val\n                smallest_index = i\n            elif val == smallest_even and i < smallest_index:\n                smallest_index = i\n    \n    if smallest_even is None:\n        return []\n    \n    return [smallest_even, smallest_index]\n```"}
{"id": "HumanEval/69", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 208, "completion_tokens": 124, "total_tokens": 332, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 208}}, "wall_s": 7.76, "content": "Here's the implementation for the function you described:\n\n```python\ndef search(lst):\n    \"\"\"\n    Returns the greatest integer that is greater than zero and has a frequency\n    greater than or equal to the integer itself. If no such value exists, returns -1.\n    \"\"\"\n    freq = {}\n    for num in lst:\n        freq[num] = freq.get(num, 0) + 1\n\n    result = -1\n    for num, count in freq.items():\n        if num > 0 and count >= num:\n            if result < num:\n                result = num\n\n    return result\n```"}
{"id": "HumanEval/70", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 167, "completion_tokens": 253, "total_tokens": 420, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 167}}, "wall_s": 13.9, "content": "Here's the implementation for the `strange_sort_list` function:\n\n```python\ndef strange_sort_list(lst):\n    \"\"\"\n    Given list of integers, return list in strange order.\n    Strange sorting, is when you start with the minimum value,\n    then maximum of the remaining integers, then minimum and so on.\n\n    Examples:\n    strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]\n    strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]\n    strange_sort_list([]) == []\n    \"\"\"\n    if not lst:\n        return []\n    \n    result = []\n    remaining = sorted(lst)\n    \n    # We alternate picking from the front (min) and back (max)\n    # of the sorted list\n    i, j = 0, len(remaining) - 1\n    take_min = True\n    \n    while i <= j:\n        if take_min:\n            result.append(remaining[i])\n            i += 1\n        else:\n            result.append(remaining[j])\n            j -= 1\n        take_min = not take_min\n    \n    return result\n```"}
{"id": "HumanEval/71", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 164, "completion_tokens": 244, "total_tokens": 408, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 164}}, "wall_s": 13.56, "content": "Here's the implementation using Heron's formula:\n\n```python\nimport math\n\ndef triangle_area(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return the area of\n    the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n    Otherwise return -1\n    Three sides make a valid triangle when the sum of any two sides is greater \n    than the third side.\n    Example:\n    triangle_area(3, 4, 5) == 6.00\n    triangle_area(1, 2, 10) == -1\n    '''\n    # Check if the sides form a valid triangle\n    if a + b > c and a + c > b and b + c > a:\n        # Calculate semi-perimeter\n        s = (a + b + c) / 2\n        # Calculate area using Heron's formula\n        area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n        # Round to 2 decimal places\n        return round(area, 2)\n    else:\n        return -1\n```"}
{"id": "HumanEval/72", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 271, "completion_tokens": 79, "total_tokens": 350, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 271}}, "wall_s": 5.85, "content": "Here's the implementation for the function you described:\n\n```python\ndef will_it_fly(q, w):\n    # Check if the list is a palindrome (balanced)\n    if q != q[::-1]:\n        return False\n    # Check if the sum of elements is less than or equal to w\n    if sum(q) > w:\n        return False\n    return True\n```"}
{"id": "HumanEval/73", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 198, "completion_tokens": 151, "total_tokens": 349, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 198}}, "wall_s": 9.05, "content": "Here's the implementation for the `smallest_change` function:\n\n```python\ndef smallest_change(arr):\n    \"\"\"\n    Given an array arr of integers, find the minimum number of elements that\n    need to be changed to make the array palindromic. A palindromic array is an array that\n    is read the same backwards and forwards. In one change, you can change one element to any other element.\n    \"\"\"\n    n = len(arr)\n    changes = 0\n    left = 0\n    right = n - 1\n    \n    while left < right:\n        if arr[left] != arr[right]:\n            changes += 1\n        left += 1\n        right -= 1\n    \n    return changes\n```"}
{"id": "HumanEval/74", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 238, "completion_tokens": 252, "total_tokens": 490, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 238}}, "wall_s": 14.29, "content": "Here's the implementation for the function you described:\n\n```python\ndef total_match(lst1, lst2):\n    '''\n    Write a function that accepts two lists of strings and returns the list that has \n    total number of chars in the all strings of the list less than the other list.\n\n    if the two lists have the same number of chars, return the first list.\n\n    Examples\n    total_match([], []) \u279e []\n    total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n    total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n    total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n    total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n    '''\n    total1 = sum(len(s) for s in lst1)\n    total2 = sum(len(s) for s in lst2)\n\n    if total1 <= total2:\n        return lst1\n    else:\n        return lst2\n```"}
{"id": "HumanEval/75", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 123, "completion_tokens": 198, "total_tokens": 321, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 123}}, "wall_s": 11.06, "content": "Here's the implementation for the function:\n\n```python\ndef is_multiply_prime(a):\n    \"\"\"Write a function that returns true if the given number is the multiplication of 3 prime numbers\n    and false otherwise.\n    Knowing that (a) is less then 100. \n    Example:\n    is_multiply_prime(30) == True\n    30 = 2 * 3 * 5\n    \"\"\"\n    if a < 2:\n        return False\n\n    # Find prime factors\n    n = a\n    factors = []\n    d = 2\n    while d * d <= n:\n        while n % d == 0:\n            factors.append(d)\n            n //= d\n        d += 1\n    if n > 1:\n        factors.append(n)\n\n    # Check if exactly 3 prime factors (allowing repeats like 2*2*2 = 8)\n    return len(factors) == 3\n```"}
{"id": "HumanEval/76", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 199, "completion_tokens": 137, "total_tokens": 336, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 199}}, "wall_s": 8.45, "content": "```python\n\ndef is_simple_power(x, n):\n    \"\"\"Returns True if x is a simple power of n (n**int == x), otherwise False.\"\"\"\n    if n == 0 or n == 1:\n        # 0**positive = 0, 0**0 = 1, 1**anything = 1\n        return x == n or x == 1\n    if x < 1:\n        return False\n    # Repeatedly divide x by n\n    while x >= n:\n        if x % n != 0:\n            return False\n        x //= n\n    return x == 1\n\n```"}
{"id": "HumanEval/77", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 153, "completion_tokens": 198, "total_tokens": 351, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 153}}, "wall_s": 11.22, "content": "```python\ndef iscube(a):\n    '''\n    Write a function that takes an integer a and returns True \n    if this integer is a cube of some integer number.\n    Note: you may assume the input is always valid.\n    Examples:\n    iscube(1) ==> True\n    iscube(2) ==> False\n    iscube(-1) ==> True\n    iscube(64) ==> True\n    iscube(0) ==> True\n    iscube(180) ==> False\n    '''\n    if a < 0:\n        # Handle negative numbers by working with absolute value\n        a = -a\n        # Check if the cube root of the absolute value is an integer\n        root = round(a ** (1/3))\n        return root * root * root == a\n    else:\n        # For non-negative numbers\n        root = round(a ** (1/3))\n        return root * root * root == a\n```"}
{"id": "HumanEval/78", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 342, "completion_tokens": 102, "total_tokens": 444, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 342}}, "wall_s": 7.24, "content": "```python\n\ndef hex_key(num):\n    \"\"\"Counts the number of hexadecimal digits that are primes.\n    Prime hex digits: 2, 3, 5, 7, B (11), D (13).\n    \"\"\"\n    prime_digits = {'2', '3', '5', '7', 'B', 'D'}\n    count = 0\n    for digit in num:\n        if digit in prime_digits:\n            count += 1\n    return count\n\n```"}
{"id": "HumanEval/79", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 186, "completion_tokens": 202, "total_tokens": 388, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 186}}, "wall_s": 11.42, "content": "\n```python\n\ndef decimal_to_binary(decimal):\n    \"\"\"You will be given a number in decimal form and your task is to convert it to\n    binary format. The function should return a string, with each character representing a binary\n    number. Each character in the string will be '0' or '1'.\n\n    There will be an extra couple of characters 'db' at the beginning and at the end of the string.\n    The extra characters are there to help with the format.\n\n    Examples:\n    decimal_to_binary(15)   # returns \"db1111db\"\n    decimal_to_binary(32)   # returns \"db100000db\"\n    \"\"\"\n    if decimal == 0:\n        return \"db0db\"\n    binary = \"\"\n    n = decimal\n    while n > 0:\n        binary = str(n % 2) + binary\n        n //= 2\n    return \"db\" + binary + \"db\"\n\n```"}
{"id": "HumanEval/80", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 165, "completion_tokens": 186, "total_tokens": 351, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 165}}, "wall_s": 10.18, "content": "```python\n\ndef is_happy(s):\n    \"\"\"You are given a string s.\n    Your task is to check if the string is happy or not.\n    A string is happy if its length is at least 3 and every 3 consecutive letters are distinct\n    For example:\n    is_happy(a) => False\n    is_happy(aa) => False\n    is_happy(abcd) => True\n    is_happy(aabb) => False\n    is_happy(adb) => True\n    is_happy(xyy) => False\n    \"\"\"\n    if len(s) < 3:\n        return False\n    for i in range(len(s) - 2):\n        if s[i] == s[i+1] or s[i] == s[i+2] or s[i+1] == s[i+2]:\n            return False\n    return True\n\n```"}
{"id": "HumanEval/81", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 316, "completion_tokens": 277, "total_tokens": 593, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 316}}, "wall_s": 14.71, "content": "Here's the implementation for the function you described:\n\n```python\ndef numerical_letter_grade(grades):\n    letter_grades = []\n    for gpa in grades:\n        if gpa == 4.0:\n            letter_grades.append('A+')\n        elif gpa > 3.7:\n            letter_grades.append('A')\n        elif gpa > 3.3:\n            letter_grades.append('A-')\n        elif gpa > 3.0:\n            letter_grades.append('B+')\n        elif gpa > 2.7:\n            letter_grades.append('B')\n        elif gpa > 2.3:\n            letter_grades.append('B-')\n        elif gpa > 2.0:\n            letter_grades.append('C+')\n        elif gpa > 1.7:\n            letter_grades.append('C')\n        elif gpa > 1.3:\n            letter_grades.append('C-')\n        elif gpa > 1.0:\n            letter_grades.append('D+')\n        elif gpa > 0.7:\n            letter_grades.append('D')\n        elif gpa > 0.0:\n            letter_grades.append('D-')\n        else:\n            letter_grades.append('E')\n    return letter_grades\n```"}
{"id": "HumanEval/82", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 125, "completion_tokens": 139, "total_tokens": 264, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 125}}, "wall_s": 7.49, "content": "Here's the implementation:\n\n```python\ndef prime_length(string):\n    \"\"\"Write a function that takes a string and returns True if the string\n    length is a prime number or False otherwise\n    Examples\n    prime_length('Hello') == True\n    prime_length('abcdcba') == True\n    prime_length('kittens') == True\n    prime_length('orange') == False\n    \"\"\"\n    length = len(string)\n    if length < 2:\n        return False\n    for i in range(2, int(length ** 0.5) + 1):\n        if length % i == 0:\n            return False\n    return True\n```"}
{"id": "HumanEval/83", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 88, "completion_tokens": 269, "total_tokens": 357, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 88}}, "wall_s": 12.88, "content": "```python\n\ndef starts_one_ends(n):\n    \"\"\"\n    Given a positive integer n, return the count of the numbers of n-digit\n    positive integers that start or end with 1.\n    \"\"\"\n    if n == 1:\n        # For 1-digit numbers: 1-9, those starting or ending with 1 are just [1]\n        return 1\n\n    # Total n-digit numbers: 9 * 10^(n-1)\n    # Numbers that start with 1: 10^(n-1)\n    # Numbers that end with 1: 9 * 10^(n-2) (first digit 1-9, last digit fixed to 1)\n    # Numbers that both start and end with 1: 10^(n-2) (first digit 1, last digit 1, middle digits any)\n    # By inclusion-exclusion:\n    # count = start_with_1 + end_with_1 - both_start_and_end_with_1\n    start_with_1 = 10 ** (n - 1)\n    end_with_1 = 9 * 10 ** (n - 2)\n    both = 10 ** (n - 2)\n    return start_with_1 + end_with_1 - both\n\n```"}
{"id": "HumanEval/84", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 176, "completion_tokens": 155, "total_tokens": 331, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 176}}, "wall_s": 8.54, "content": "```python\n\ndef solve(N):\n    \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n    \n    Example\n        For N = 1000, the sum of digits will be 1 the output should be \"1\".\n        For N = 150, the sum of digits will be 6 the output should be \"110\".\n        For N = 147, the sum of digits will be 12 the output should be \"1100\".\n    \n    Variables:\n        @N integer\n             Constraints: 0 \u2264 N \u2264 10000.\n    Output:\n         a string of binary number\n    \"\"\"\n    digit_sum = sum(int(d) for d in str(N))\n    return bin(digit_sum)[2:]\n\n```"}
{"id": "HumanEval/85", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 98, "completion_tokens": 114, "total_tokens": 212, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 98}}, "wall_s": 6.33, "content": "\n```python\n\nfrom typing import List\n\ndef add(lst: List[int]) -> int:\n    \"\"\"\n    Given a non-empty list of integers lst, add the even elements that are at odd indices.\n    \n    Examples:\n        add([4, 2, 6, 7]) ==> 2\n    \"\"\"\n    total = 0\n    for i in range(1, len(lst), 2):  # odd indices only\n        if lst[i] % 2 == 0:\n            total += lst[i]\n    return total\n\n```"}
{"id": "HumanEval/86", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 177, "completion_tokens": 189, "total_tokens": 366, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 177}}, "wall_s": 9.9, "content": "Here's the implementation for the `anti_shuffle` function:\n\n```python\ndef anti_shuffle(s):\n    \"\"\"\n    Write a function that takes a string and returns an ordered version of it.\n    Ordered version of string, is a string where all words (separated by space)\n    are replaced by a new word where all the characters arranged in\n    ascending order based on ascii value.\n    Note: You should keep the order of words and blank spaces in the sentence.\n\n    For example:\n    anti_shuffle('Hi') returns 'Hi'\n    anti_shuffle('hello') returns 'ehllo'\n    anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n    \"\"\"\n    words = s.split(' ')\n    ordered_words = []\n    for word in words:\n        ordered_word = ''.join(sorted(word))\n        ordered_words.append(ordered_word)\n    return ' '.join(ordered_words)\n```"}
{"id": "HumanEval/87", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 303, "completion_tokens": 95, "total_tokens": 398, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 303}}, "wall_s": 6.4, "content": "Here's the implementation for the function you described:\n\n```python\ndef get_row(lst, x):\n    result = []\n    for row_idx, row in enumerate(lst):\n        for col_idx, value in enumerate(row):\n            if value == x:\n                result.append((row_idx, col_idx))\n    \n    # Sort by row ascending, then by column descending\n    result.sort(key=lambda coord: (coord[0], -coord[1]))\n    return result\n```"}
{"id": "HumanEval/88", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 246, "completion_tokens": 301, "total_tokens": 547, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 246}}, "wall_s": 15.41, "content": "```python\n\ndef sort_array(array):\n    \"\"\"\n    Given an array of non-negative integers, return a copy of the given array after sorting,\n    you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n    or sort it in descending order if the sum( first index value, last index value) is even.\n\n    Note:\n    * don't change the given array.\n\n    Examples:\n    * sort_array([]) => []\n    * sort_array([5]) => [5]\n    * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]\n    * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]\n    \"\"\"\n    if len(array) == 0:\n        return []\n    if len(array) == 1:\n        return [array[0]]\n    \n    first = array[0]\n    last = array[-1]\n    total = first + last\n    \n    result = array.copy()\n    \n    if total % 2 == 1:  # odd sum -> ascending\n        result.sort()\n    else:               # even sum -> descending\n        result.sort(reverse=True)\n    \n    return result\n\n```"}
{"id": "HumanEval/89", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 154, "completion_tokens": 233, "total_tokens": 387, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 154}}, "wall_s": 11.99, "content": "\n```python\n\ndef encrypt(s):\n    \"\"\"Create a function encrypt that takes a string as an argument and\n    returns a string encrypted with the alphabet being rotated. \n    The alphabet should be rotated in a manner such that the letters \n    shift down by two multiplied to two places.\n    For example:\n    encrypt('hi') returns 'lm'\n    encrypt('asdfghjkl') returns 'ewhjklnop'\n    encrypt('gf') returns 'kj'\n    encrypt('et') returns 'ix'\n    \"\"\"\n    result = []\n    for ch in s:\n        if 'a' <= ch <= 'z':\n            # shift by 4 positions (2 * 2)\n            shifted = chr((ord(ch) - ord('a') + 4) % 26 + ord('a'))\n            result.append(shifted)\n        elif 'A' <= ch <= 'Z':\n            shifted = chr((ord(ch) - ord('A') + 4) % 26 + ord('A'))\n            result.append(shifted)\n        else:\n            result.append(ch)\n    return ''.join(result)\n\n```"}
{"id": "HumanEval/90", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 173, "completion_tokens": 200, "total_tokens": 373, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 173}}, "wall_s": 10.58, "content": "```python\n\ndef next_smallest(lst):\n    \"\"\"\n    You are given a list of integers.\n    Write a function next_smallest() that returns the 2nd smallest element of the list.\n    Return None if there is no such element.\n    \n    next_smallest([1, 2, 3, 4, 5]) == 2\n    next_smallest([5, 1, 4, 3, 2]) == 2\n    next_smallest([]) == None\n    next_smallest([1, 1]) == None\n    \"\"\"\n    # Remove duplicates by converting to a set, then sort unique values\n    unique_sorted = sorted(set(lst))\n    # If there are fewer than 2 unique elements, return None\n    if len(unique_sorted) < 2:\n        return None\n    # Return the second smallest unique element\n    return unique_sorted[1]\n\n```"}
{"id": "HumanEval/91", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 151, "completion_tokens": 171, "total_tokens": 322, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 151}}, "wall_s": 9.19, "content": "Here's the implementation:\n\n```python\ndef is_bored(S):\n    \"\"\"\n    You'll be given a string of words, and your task is to count the number\n    of boredoms. A boredom is a sentence that starts with the word \"I\".\n    Sentences are delimited by '.', '?' or '!'.\n   \n    For example:\n    >>> is_bored(\"Hello world\")\n    0\n    >>> is_bored(\"The sky is blue. The sun is shining. I love this weather\")\n    1\n    \"\"\"\n    import re\n    sentences = re.split(r'[.!?]', S)\n    count = 0\n    for sentence in sentences:\n        stripped = sentence.strip()\n        if stripped.startswith(\"I \") or stripped == \"I\":\n            count += 1\n    return count\n```"}
{"id": "HumanEval/92", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 178, "completion_tokens": 215, "total_tokens": 393, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 178}}, "wall_s": 11.12, "content": "Here's the implementation for the function you described:\n\n```python\ndef any_int(x, y, z):\n    '''\n    Create a function that takes 3 numbers.\n    Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n    Returns false in any other cases.\n    \n    Examples\n    any_int(5, 2, 7) \u279e True\n    \n    any_int(3, 2, 2) \u279e False\n\n    any_int(3, -2, 1) \u279e True\n    \n    any_int(3.6, -2.2, 2) \u279e False\n    '''\n    # Check if all inputs are integers\n    if not (isinstance(x, int) and isinstance(y, int) and isinstance(z, int)):\n        return False\n    \n    # Check if one number equals the sum of the other two\n    return (x == y + z) or (y == x + z) or (z == x + y)\n```"}
{"id": "HumanEval/93", "passed": false, "detail": "Traceback (most recent call last):\n  File \"<string>\", line 35, in <module>\n    check(encode)\n    ~~~~~^^^^^^^^\n  File \"<string>\", line 26, in check\n    assert candidate('TEST') == 'tgst', \"This prints if this assert fails 1 (good for debugging!)\"\n           ^^^^^^^^^^^^^^^^^^^^^^^^^^^\nAssertionError: This prints if this assert fails 1 (good for debugging!)", "finish_reason": "stop", "usage": {"prompt_tokens": 152, "completion_tokens": 137, "total_tokens": 289, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 152}}, "wall_s": 7.67, "content": "Here's the implementation for the `encode` function:\n\n```python\ndef encode(message):\n    vowels = 'aeiouAEIOU'\n    result = []\n    for char in message:\n        if char in vowels:\n            # Shift vowel 2 places ahead in the alphabet\n            shifted = chr(ord(char) + 2)\n            result.append(shifted)\n        elif char.isalpha():\n            # Swap case for non-vowel letters\n            if char.islower():\n                result.append(char.upper())\n            else:\n                result.append(char.lower())\n        else:\n            # Keep non-letter characters as is\n            result.append(char)\n    return ''.join(result)\n```"}
{"id": "HumanEval/94", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 329, "completion_tokens": 130, "total_tokens": 459, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 329}}, "wall_s": 8.1, "content": "Here's the implementation:\n\n```python\ndef skjkasdkd(lst):\n    def is_prime(n):\n        if n < 2:\n            return False\n        for i in range(2, int(n ** 0.5) + 1):\n            if n % i == 0:\n                return False\n        return True\n\n    largest_prime = 0\n    for num in lst:\n        if is_prime(num) and num > largest_prime:\n            largest_prime = num\n\n    if largest_prime == 0:\n        return 0\n\n    return sum(int(digit) for digit in str(largest_prime))\n```"}
{"id": "HumanEval/95", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 223, "completion_tokens": 169, "total_tokens": 392, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 223}}, "wall_s": 9.35, "content": "```python\n\ndef check_dict_case(dict):\n    \"\"\"\n    Given a dictionary, return True if all keys are strings in lower \n    case or all keys are strings in upper case, else return False.\n    The function should return False is the given dictionary is empty.\n    \"\"\"\n    if not dict:\n        return False\n    \n    lower_case = True\n    upper_case = True\n    \n    for key in dict.keys():\n        if not isinstance(key, str):\n            lower_case = False\n            upper_case = False\n            break\n        if not key.islower():\n            lower_case = False\n        if not key.isupper():\n            upper_case = False\n        # If both are already False, no need to continue\n        if not lower_case and not upper_case:\n            break\n    \n    return lower_case or upper_case\n\n```"}
{"id": "HumanEval/96", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 188, "completion_tokens": 228, "total_tokens": 416, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 188}}, "wall_s": 11.62, "content": "```python\n\ndef count_up_to(n):\n    \"\"\"Implement a function that takes an non-negative integer and returns an array of the first n\n    integers that are prime numbers and less than n.\n    for example:\n    count_up_to(5) => [2,3]\n    count_up_to(11) => [2,3,5,7]\n    count_up_to(0) => []\n    count_up_to(20) => [2,3,5,7,11,13,17,19]\n    count_up_to(1) => []\n    count_up_to(18) => [2,3,5,7,11,13,17]\n    \"\"\"\n    def is_prime(num):\n        if num < 2:\n            return False\n        for i in range(2, int(num ** 0.5) + 1):\n            if num % i == 0:\n                return False\n        return True\n\n    result = []\n    for candidate in range(2, n):\n        if is_prime(candidate):\n            result.append(candidate)\n    return result\n\n```"}
{"id": "HumanEval/97", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 141, "completion_tokens": 141, "total_tokens": 282, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 141}}, "wall_s": 7.68, "content": "```python\ndef multiply(a, b):\n    \"\"\"Complete the function that takes two integers and returns \n    the product of their unit digits.\n    Assume the input is always valid.\n    Examples:\n    multiply(148, 412) should return 16.\n    multiply(19, 28) should return 72.\n    multiply(2020, 1851) should return 0.\n    multiply(14,-15) should return 20.\n    \"\"\"\n    # Get the unit digit of a (absolute value to handle negatives)\n    unit_a = abs(a) % 10\n    unit_b = abs(b) % 10\n    return unit_a * unit_b\n```"}
{"id": "HumanEval/98", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 120, "completion_tokens": 128, "total_tokens": 248, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 120}}, "wall_s": 6.92, "content": "Here's the implementation:\n\n```python\ndef count_upper(s):\n    \"\"\"\n    Given a string s, count the number of uppercase vowels in even indices.\n    \n    For example:\n    count_upper('aBCdEf') returns 1\n    count_upper('abcdefg') returns 0\n    count_upper('dBBE') returns 0\n    \"\"\"\n    vowels = set('AEIOU')\n    count = 0\n    for i, ch in enumerate(s):\n        if i % 2 == 0 and ch in vowels:\n            count += 1\n    return count\n```"}
{"id": "HumanEval/99", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 199, "completion_tokens": 211, "total_tokens": 410, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 199}}, "wall_s": 10.9, "content": "Here's the implementation for the function you described:\n\n```python\ndef closest_integer(value):\n    '''\n    Create a function that takes a value (string) representing a number\n    and returns the closest integer to it. If the number is equidistant\n    from two integers, round it away from zero.\n\n    Examples\n    >>> closest_integer(\"10\")\n    10\n    >>> closest_integer(\"15.3\")\n    15\n\n    Note:\n    Rounding away from zero means that if the given number is equidistant\n    from two integers, the one you should return is the one that is the\n    farthest from zero. For example closest_integer(\"14.5\") should\n    return 15 and closest_integer(\"-14.5\") should return -15.\n    '''\n    from decimal import Decimal, ROUND_HALF_UP\n    num = Decimal(value)\n    rounded = num.to_integral_value(rounding=ROUND_HALF_UP)\n    return int(rounded)\n```"}
{"id": "HumanEval/100", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 175, "completion_tokens": 203, "total_tokens": 378, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 175}}, "wall_s": 10.42, "content": "Here's the implementation for the function you described:  \n\n```python\ndef make_a_pile(n):\n    \"\"\"\n    Given a positive integer n, you have to make a pile of n levels of stones.\n    The first level has n stones.\n    The number of stones in the next level is:\n        - the next odd number if n is odd.\n        - the next even number if n is even.\n    Return the number of stones in each level in a list, where element at index\n    i represents the number of stones in the level (i+1).\n\n    Examples:\n    >>> make_a_pile(3)\n    [3, 5, 7]\n    \"\"\"\n    result = []\n    current = n\n    for _ in range(n):\n        result.append(current)\n        # Determine parity of the original n to decide increment\n        if n % 2 == 0:\n            current += 2\n        else:\n            current += 2\n    return result\n```"}
{"id": "HumanEval/101", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 159, "completion_tokens": 90, "total_tokens": 249, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 159}}, "wall_s": 5.45, "content": "\n```python\n\nimport re\n\ndef words_string(s):\n    \"\"\"\n    Splits a string of words separated by commas or spaces into a list of words.\n    \"\"\"\n    # Split on commas or spaces (one or more)\n    words = re.split(r'[,\\s]+', s.strip())\n    # Remove any empty strings that might result from leading/trailing separators\n    return [w for w in words if w]\n\n```"}
{"id": "HumanEval/102", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 137, "completion_tokens": 151, "total_tokens": 288, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 137}}, "wall_s": 7.97, "content": "```python\n\ndef choose_num(x, y):\n    \"\"\"This function takes two positive numbers x and y and returns the\n    biggest even integer number that is in the range [x, y] inclusive. If \n    there's no such number, then the function should return -1.\n\n    For example:\n    choose_num(12, 15) = 14\n    choose_num(13, 12) = -1\n    \"\"\"\n    if x > y:\n        return -1\n    # Start from the largest number in the range and go downwards\n    for num in range(y, x - 1, -1):\n        if num % 2 == 0:\n            return num\n    return -1\n\n```"}
{"id": "HumanEval/103", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 188, "completion_tokens": 219, "total_tokens": 407, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 188}}, "wall_s": 11.3, "content": "Here's the implementation for the function you described:\n\n```python\ndef rounded_avg(n, m):\n    \"\"\"You are given two positive integers n and m, and your task is to compute the\n    average of the integers from n through m (including n and m). \n    Round the answer to the nearest integer and convert that to binary.\n    If n is greater than m, return -1.\n    Example:\n    rounded_avg(1, 5) => \"0b11\"\n    rounded_avg(7, 5) => -1\n    rounded_avg(10, 20) => \"0b1111\"\n    rounded_avg(20, 33) => \"0b11010\"\n    \"\"\"\n    if n > m:\n        return -1\n    \n    total = 0\n    count = 0\n    for i in range(n, m + 1):\n        total += i\n        count += 1\n    \n    avg = total / count\n    rounded = round(avg)\n    return bin(rounded)\n```"}
{"id": "HumanEval/104", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 149, "completion_tokens": 142, "total_tokens": 291, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 149}}, "wall_s": 8.07, "content": "```python\n\ndef unique_digits(x):\n    \"\"\"Given a list of positive integers x. return a sorted list of all \n    elements that hasn't any even digit.\n\n    Note: Returned list should be sorted in increasing order.\n    \n    For example:\n    >>> unique_digits([15, 33, 1422, 1])\n    [1, 15, 33]\n    >>> unique_digits([152, 323, 1422, 10])\n    []\n    \"\"\"\n    result = []\n    for num in x:\n        if all(int(d) % 2 != 0 for d in str(num)):\n            result.append(num)\n    return sorted(result)\n\n```"}
{"id": "HumanEval/105", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 319, "completion_tokens": 244, "total_tokens": 563, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 319}}, "wall_s": 13.3, "content": "Here's the implementation for the function you described:\n\n```python\ndef by_length(arr):\n    \"\"\"\n    Given an array of integers, sort the integers that are between 1 and 9 inclusive,\n    reverse the resulting array, and then replace each digit by its corresponding name from\n    \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n    \"\"\"\n    # Filter numbers between 1 and 9 inclusive\n    filtered = [x for x in arr if 1 <= x <= 9]\n    \n    # Sort the filtered list\n    filtered.sort()\n    \n    # Reverse the sorted list\n    filtered.reverse()\n    \n    # Map numbers to their word equivalents\n    num_to_word = {\n        1: \"One\",\n        2: \"Two\",\n        3: \"Three\",\n        4: \"Four\",\n        5: \"Five\",\n        6: \"Six\",\n        7: \"Seven\",\n        8: \"Eight\",\n        9: \"Nine\"\n    }\n    \n    # Convert each number to its word form\n    result = [num_to_word[num] for num in filtered]\n    \n    return result\n```"}
{"id": "HumanEval/106", "passed": false, "detail": "Traceback (most recent call last):\n  File \"<string>\", line 32, in <module>\n    check(f)\n    ~~~~~^^^\n  File \"<string>\", line 27, in check\n    assert candidate(5) == [1, 2, 6, 24, 15]\n           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^\nAssertionError", "finish_reason": "stop", "usage": {"prompt_tokens": 167, "completion_tokens": 124, "total_tokens": 291, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 167}}, "wall_s": 7.23, "content": "\n```python\n\ndef f(n):\n    def factorial(k):\n        result = 1\n        for i in range(1, k + 1):\n            result *= i\n        return result\n\n    def sum_to(k):\n        total = 0\n        for i in range(1, k + 1):\n            total += i\n        return total\n\n    result = []\n    for i in range(1, n + 1):\n        if i % 2 == 0:\n            result.append(sum_to(i))\n        else:\n            result.append(factorial(i))\n    return result\n\n```"}
{"id": "HumanEval/107", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 252, "completion_tokens": 130, "total_tokens": 382, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 252}}, "wall_s": 7.94, "content": "```python\n\ndef even_odd_palindrome(n):\n    \"\"\"\n    Given a positive integer n, return a tuple that has the number of even and odd\n    integer palindromes that fall within the range(1, n), inclusive.\n    \"\"\"\n    even_count = 0\n    odd_count = 0\n    for num in range(1, n + 1):\n        s = str(num)\n        if s == s[::-1]:\n            if num % 2 == 0:\n                even_count += 1\n            else:\n                odd_count += 1\n    return (even_count, odd_count)\n\n```"}
{"id": "HumanEval/108", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 173, "completion_tokens": 265, "total_tokens": 438, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 173}}, "wall_s": 13.93, "content": "Here's the implementation for the function you described:\n\n```python\ndef count_nums(arr):\n    \"\"\"\n    Write a function count_nums which takes an array of integers and returns\n    the number of elements which has a sum of digits > 0.\n    If a number is negative, then its first signed digit will be negative:\n    e.g. -123 has signed digits -1, 2, and 3.\n    >>> count_nums([]) == 0\n    >>> count_nums([-1, 11, -11]) == 1\n    >>> count_nums([1, 1, 2]) == 3\n    \"\"\"\n    count = 0\n    for num in arr:\n        if num == 0:\n            continue\n        if num > 0:\n            digits = list(map(int, str(num)))\n            if sum(digits) > 0:\n                count += 1\n        else:\n            # Negative number: treat first digit as negative\n            num_str = str(num)[1:]  # remove the minus sign\n            digits = list(map(int, num_str))\n            digits[0] = -digits[0]\n            if sum(digits) > 0:\n                count += 1\n    return count\n```"}
{"id": "HumanEval/109", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 347, "completion_tokens": 148, "total_tokens": 495, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 347}}, "wall_s": 9.16, "content": "```python\n\ndef move_one_ball(arr):\n    \"\"\"\n    Determines if the array can be sorted in non-decreasing order by performing\n    any number of right shift operations.\n    \"\"\"\n    if not arr:\n        return True\n    \n    n = len(arr)\n    # Find the number of \"break points\" where arr[i] > arr[(i+1) % n]\n    # In a sorted array after some rotations, there should be at most one such break.\n    breaks = 0\n    for i in range(n):\n        if arr[i] > arr[(i + 1) % n]:\n            breaks += 1\n            if breaks > 1:\n                return False\n    return True\n\n```"}
{"id": "HumanEval/110", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 240, "completion_tokens": 274, "total_tokens": 514, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 240}}, "wall_s": 14.59, "content": "```python\n\ndef exchange(lst1, lst2):\n    \"\"\"In this problem, you will implement a function that takes two lists of numbers,\n    and determines whether it is possible to perform an exchange of elements\n    between them to make lst1 a list of only even numbers.\n    There is no limit on the number of exchanged elements between lst1 and lst2.\n    If it is possible to exchange elements between the lst1 and lst2 to make\n    all the elements of lst1 to be even, return \"YES\".\n    Otherwise, return \"NO\".\n    For example:\n    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => \"YES\"\n    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => \"NO\"\n    It is assumed that the input lists will be non-empty.\n    \"\"\"\n    odd_in_lst1 = [x for x in lst1 if x % 2 != 0]\n    even_in_lst2 = [x for x in lst2 if x % 2 == 0]\n    \n    if len(odd_in_lst1) <= len(even_in_lst2):\n        return \"YES\"\n    else:\n        return \"NO\"\n\n```"}
{"id": "HumanEval/111", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 194, "completion_tokens": 227, "total_tokens": 421, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 194}}, "wall_s": 12.16, "content": "Here's the implementation for the `histogram` function:\n\n```python\ndef histogram(test):\n    \"\"\"Given a string representing a space separated lowercase letters, return a dictionary\n    of the letter with the most repetition and containing the corresponding count.\n    If several letters have the same occurrence, return all of them.\n    \n    Example:\n    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}\n    histogram('a b b a') == {'a': 2, 'b': 2}\n    histogram('a b c a b') == {'a': 2, 'b': 2}\n    histogram('b b b b a') == {'b': 4}\n    histogram('') == {}\n\n    \"\"\"\n    if not test:\n        return {}\n    \n    counts = {}\n    for char in test.split():\n        counts[char] = counts.get(char, 0) + 1\n    \n    max_count = max(counts.values())\n    return {char: count for char, count in counts.items() if count == max_count}\n```"}
{"id": "HumanEval/112", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 207, "completion_tokens": 79, "total_tokens": 286, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 207}}, "wall_s": 5.41, "content": "Here's the implementation for the function:\n\n```python\ndef reverse_delete(s, c):\n    # Remove characters from s that are in c\n    result = ''.join(ch for ch in s if ch not in c)\n    # Check if the result string is a palindrome\n    is_palindrome = result == result[::-1]\n    return (result, is_palindrome)\n```"}
{"id": "HumanEval/113", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 218, "completion_tokens": 251, "total_tokens": 469, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 218}}, "wall_s": 13.39, "content": "Here's the implementation for the function you described:\n\n```python\ndef odd_count(lst):\n    \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n    Each element i of the output should be \"the number of odd elements in the\n    string i of the input.\" where all the i's should be replaced by the number\n    of odd digits in the i'th string of the input.\n\n    >>> odd_count(['1234567'])\n    [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n    >>> odd_count(['3',\"11111111\"])\n    [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n     \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n    \"\"\"\n    result = []\n    for s in lst:\n        count = sum(1 for ch in s if int(ch) % 2 != 0)\n        result.append(\n            f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n        )\n    return result\n```"}
{"id": "HumanEval/114", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 133, "completion_tokens": 169, "total_tokens": 302, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 133}}, "wall_s": 9.28, "content": "```python\n\ndef minSubArraySum(nums):\n    \"\"\"\n    Given an array of integers nums, find the minimum sum of any non-empty sub-array\n    of nums.\n    Example\n    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n    minSubArraySum([-1, -2, -3]) == -6\n    \"\"\"\n    min_ending_here = nums[0]\n    min_so_far = nums[0]\n    for i in range(1, len(nums)):\n        min_ending_here = min(nums[i], min_ending_here + nums[i])\n        min_so_far = min(min_so_far, min_ending_here)\n    return min_so_far\n\n```"}
{"id": "HumanEval/115", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 370, "completion_tokens": 386, "total_tokens": 756, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 370}}, "wall_s": 20.58, "content": "```python\n\ndef max_fill(grid, capacity):\n    import math\n    \"\"\"\n    You are given a rectangular grid of wells. Each row represents a single well,\n    and each 1 in a row represents a single unit of water.\n    Each well has a corresponding bucket that can be used to extract water from it, \n    and all buckets have the same capacity.\n    Your task is to use the buckets to empty the wells.\n    Output the number of times you need to lower the buckets.\n\n    Example 1:\n        Input: \n            grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]\n            bucket_capacity : 1\n        Output: 6\n\n    Example 2:\n        Input: \n            grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]\n            bucket_capacity : 2\n        Output: 5\n    \n    Example 3:\n        Input: \n            grid : [[0,0,0], [0,0,0]]\n            bucket_capacity : 5\n        Output: 0\n\n    Constraints:\n        * all wells have the same length\n        * 1 <= grid.length <= 10^2\n        * 1 <= grid[:,1].length <= 10^2\n        * grid[i][j] -> 0 | 1\n        * 1 <= capacity <= 10\n    \"\"\"\n    total_bucket_lowerings = 0\n    for row in grid:\n        water_units = sum(row)\n        if water_units > 0:\n            total_bucket_lowerings += math.ceil(water_units / capacity)\n    return total_bucket_lowerings\n\n```"}
{"id": "HumanEval/116", "passed": false, "detail": "Traceback (most recent call last):\n  File \"<string>\", line 39, in <module>\n    check(sort_array)\n    ~~~~~^^^^^^^^^^^^\n  File \"<string>\", line 27, in check\n    assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]\n           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^\nAssertionError", "finish_reason": "stop", "usage": {"prompt_tokens": 214, "completion_tokens": 154, "total_tokens": 368, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 214}}, "wall_s": 8.89, "content": "\n```python\n\ndef sort_array(arr):\n    \"\"\"\n    Sort an array of integers according to number of ones in their binary\n    representation in ascending order. For similar number of ones, sort based\n    on decimal value.\n    \"\"\"\n    def count_ones(x):\n        # Count ones in binary representation for non-negative numbers\n        # For negative numbers, use the two's complement representation\n        # (32-bit signed integer)\n        if x >= 0:\n            return bin(x).count('1')\n        else:\n            # For negative numbers, treat as 32-bit two's complement\n            return bin(x & 0xFFFFFFFF).count('1')\n\n    return sorted(arr, key=lambda x: (count_ones(x), x))\n\n```"}
{"id": "HumanEval/117", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 223, "completion_tokens": 253, "total_tokens": 476, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 223}}, "wall_s": 13.61, "content": "Here's the implementation for the function you described:\n\n```python\ndef select_words(s, n):\n    \"\"\"Given a string s and a natural number n, you have been tasked to implement \n    a function that returns a list of all words from string s that contain exactly \n    n consonants, in order these words appear in the string s.\n    If the string s is empty then the function should return an empty list.\n    Note: you may assume the input string contains only letters and spaces.\n    Examples:\n    select_words(\"Mary had a little lamb\", 4) ==> [\"little\"]\n    select_words(\"Mary had a little lamb\", 3) ==> [\"Mary\", \"lamb\"]\n    select_words(\"simple white space\", 2) ==> []\n    select_words(\"Hello world\", 4) ==> [\"world\"]\n    select_words(\"Uncle sam\", 3) ==> [\"Uncle\"]\n    \"\"\"\n    vowels = set(\"aeiouAEIOU\")\n    result = []\n    words = s.split()\n    for word in words:\n        consonant_count = sum(1 for ch in word if ch.isalpha() and ch not in vowels)\n        if consonant_count == n:\n            result.append(word)\n    return result\n```"}
{"id": "HumanEval/118", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 191, "completion_tokens": 123, "total_tokens": 314, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 191}}, "wall_s": 7.36, "content": "Here's the implementation for the function you described:\n\n```python\ndef get_closest_vowel(word):\n    vowels = set(\"aeiouAEIOU\")\n    \n    # Find the rightmost vowel that is between two consonants\n    for i in range(len(word) - 2, 0, -1):\n        if word[i] in vowels:\n            # Check if the character before and after are consonants\n            if word[i-1].lower() not in \"aeiou\" and word[i+1].lower() not in \"aeiou\":\n                return word[i]\n    \n    return \"\"\n```"}
{"id": "HumanEval/119", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 214, "completion_tokens": 296, "total_tokens": 510, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 214}}, "wall_s": 15.65, "content": "Here's the implementation for the function you described:\n\n```python\ndef match_parens(lst):\n    '''\n    You are given a list of two strings, both strings consist of open\n    parentheses '(' or close parentheses ')' only.\n    Your job is to check if it is possible to concatenate the two strings in\n    some order, that the resulting string will be good.\n    A string S is considered to be good if and only if all parentheses in S\n    are balanced. For example: the string '(())()' is good, while the string\n    '())' is not.\n    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n    Examples:\n    match_parens(['()(', ')']) == 'Yes'\n    match_parens([')', ')']) == 'No'\n    '''\n    def is_balanced(s):\n        bal = 0\n        for ch in s:\n            if ch == '(':\n                bal += 1\n            else:\n                bal -= 1\n            if bal < 0:\n                return False\n        return bal == 0\n\n    # Try both possible concatenations\n    for order in [(0, 1), (1, 0)]:\n        combined = lst[order[0]] + lst[order[1]]\n        if is_balanced(combined):\n            return 'Yes'\n    return 'No'\n```"}
{"id": "HumanEval/120", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 257, "completion_tokens": 73, "total_tokens": 330, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 257}}, "wall_s": 5.35, "content": "Here's the implementation for the `maximum` function:  \n\n```python\ndef maximum(arr, k):\n    \"\"\"\n    Given an array arr of integers and a positive integer k, return a sorted list \n    of length k with the maximum k numbers in arr.\n    \"\"\"\n    arr.sort()\n    return arr[-k:] if k > 0 else []\n```"}
{"id": "HumanEval/121", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 140, "completion_tokens": 77, "total_tokens": 217, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 140}}, "wall_s": 4.9, "content": "```python\ndef solution(lst):\n    \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n    total = 0\n    for i in range(len(lst)):\n        if i % 2 == 0 and lst[i] % 2 != 0:\n            total += lst[i]\n    return total\n```"}
{"id": "HumanEval/122", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 170, "completion_tokens": 109, "total_tokens": 279, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 170}}, "wall_s": 6.69, "content": "```python\n\ndef add_elements(arr, k):\n    \"\"\"\n    Given a non-empty array of integers arr and an integer k, return\n    the sum of the elements with at most two digits from the first k elements of arr.\n    \"\"\"\n    total = 0\n    for i in range(k):\n        # Check if the number has at most two digits (i.e., between -99 and 99 inclusive)\n        if -99 <= arr[i] <= 99:\n            total += arr[i]\n    return total\n\n```"}
{"id": "HumanEval/123", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 273, "completion_tokens": 322, "total_tokens": 595, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 273}}, "wall_s": 17.1, "content": "Here's the implementation for the function you described:\n\n```python\ndef get_odd_collatz(n):\n    \"\"\"\n    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n\n    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n    as follows: start with any positive integer n. Then each term is obtained from the \n    previous term as follows: if the previous term is even, the next term is one half of \n    the previous term. If the previous term is odd, the next term is 3 times the previous\n    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n\n    Note: \n        1. Collatz(1) is [1].\n        2. returned list sorted in increasing order.\n\n    For example:\n    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n    \"\"\"\n    sequence = []\n    current = n\n    while current != 1:\n        if current % 2 == 1:\n            sequence.append(current)\n        if current % 2 == 0:\n            current //= 2\n        else:\n            current = 3 * current + 1\n    sequence.append(1)  # include the final 1\n    sequence.sort()\n    return sequence\n```"}
{"id": "HumanEval/124", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 304, "completion_tokens": 494, "total_tokens": 798, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 304}}, "wall_s": 25.32, "content": "Here's the complete implementation for the `valid_date` function:\n\n```python\nimport re\n\ndef valid_date(date):\n    \"\"\"You have to write a function which validates a given date string and\n    returns True if the date is valid otherwise False.\n    The date is valid if all of the following rules are satisfied:\n    1. The date string is not empty.\n    2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.\n    3. The months should not be less than 1 or higher than 12.\n    4. The date should be in the format: mm-dd-yyyy\n\n    for example: \n    valid_date('03-11-2000') => True\n\n    valid_date('15-01-2012') => False\n\n    valid_date('04-0-2040') => False\n\n    valid_date('06-04-2020') => True\n\n    valid_date('06/04/2020') => False\n    \"\"\"\n    if not date:\n        return False\n    \n    # Check format: mm-dd-yyyy\n    if not re.match(r'^\\d{2}-\\d{2}-\\d{4}$', date):\n        return False\n    \n    parts = date.split('-')\n    month = int(parts[0])\n    day = int(parts[1])\n    year = int(parts[2])\n    \n    # Month validation\n    if month < 1 or month > 12:\n        return False\n    \n    # Day validation based on month\n    days_in_month = {\n        1: 31, 2: 29, 3: 31, 4: 30, 5: 31, 6: 30,\n        7: 31, 8: 31, 9: 30, 10: 31, 11: 30, 12: 31\n    }\n    \n    if day < 1 or day > days_in_month.get(month, 0):\n        return False\n    \n    return True\n```"}
{"id": "HumanEval/125", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 187, "completion_tokens": 196, "total_tokens": 383, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 187}}, "wall_s": 10.72, "content": "Here's the implementation for the function you described:\n\n```python\ndef split_words(txt):\n    \"\"\"\n    Given a string of words, return a list of words split on whitespace, if no whitespace exists in the text you\n    should split on commas ',' if no commas exist you should return the number of lower-case letters with odd order in the\n    alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n    \"\"\"\n    if ' ' in txt:\n        return txt.split()\n    if ',' in txt:\n        return txt.split(',')\n    # No whitespace and no commas: count lowercase letters with odd alphabetical order\n    count = 0\n    for ch in txt:\n        if 'a' <= ch <= 'z':\n            if (ord(ch) - ord('a')) % 2 == 1:\n                count += 1\n    return count\n```"}
{"id": "HumanEval/126", "passed": false, "detail": "Traceback (most recent call last):\n  File \"<string>\", line 46, in <module>\n    check(is_sorted)\n    ~~~~~^^^^^^^^^^^\n  File \"<string>\", line 42, in check\n    assert candidate([1, 2, 2, 3, 3, 4]) == True, \"This prints if this assert fails 7 (good for debugging!)\"\n           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^\nAssertionError: This prints if this assert fails 7 (good for debugging!)", "finish_reason": "stop", "usage": {"prompt_tokens": 301, "completion_tokens": 150, "total_tokens": 451, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 301}}, "wall_s": 9.01, "content": "Here's the implementation for the function you described:\n\n```python\ndef is_sorted(lst):\n    \"\"\"\n    Given a list of numbers, return whether or not they are sorted\n    in ascending order. If list has more than 1 duplicate of the same\n    number, return False. Assume no negative numbers and only integers.\n    \"\"\"\n    if len(lst) <= 1:\n        return True\n\n    for i in range(1, len(lst)):\n        if lst[i] < lst[i - 1]:\n            return False\n\n    # Check for duplicates appearing more than once\n    seen = set()\n    for num in lst:\n        if num in seen:\n            return False\n        seen.add(num)\n\n    return True\n```"}
{"id": "HumanEval/127", "passed": false, "detail": "Traceback (most recent call last):\n  File \"<string>\", line 41, in <module>\n    check(intersection)\n    ~~~~~^^^^^^^^^^^^^^\n  File \"<string>\", line 30, in check\n    assert candidate((-1, 1), (0, 4)) == \"NO\"\n           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^\nAssertionError", "finish_reason": "stop", "usage": {"prompt_tokens": 298, "completion_tokens": 156, "total_tokens": 454, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 298}}, "wall_s": 9.76, "content": "Here's the implementation:\n\n```python\ndef intersection(interval1, interval2):\n    # Determine the intersection range\n    start = max(interval1[0], interval2[0])\n    end = min(interval1[1], interval2[1])\n    \n    # If no overlap, return \"NO\"\n    if start > end:\n        return \"NO\"\n    \n    # Length of the intersection\n    length = end - start + 1\n    \n    # Check if length is prime\n    if length < 2:\n        return \"NO\"\n    \n    for i in range(2, int(length ** 0.5) + 1):\n        if length % i == 0:\n            return \"NO\"\n    \n    return \"YES\"\n```"}
{"id": "HumanEval/128", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 164, "completion_tokens": 208, "total_tokens": 372, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 164}}, "wall_s": 11.75, "content": "\n```python\n\ndef prod_signs(arr):\n    \"\"\"\n    You are given an array arr of integers and you need to return\n    sum of magnitudes of integers multiplied by product of all signs\n    of each number in the array, represented by 1, -1 or 0.\n    Note: return None for empty arr.\n\n    Example:\n    >>> prod_signs([1, 2, 2, -4]) == -9\n    >>> prod_signs([0, 1]) == 0\n    >>> prod_signs([]) == None\n    \"\"\"\n    if not arr:\n        return None\n\n    sum_magnitudes = 0\n    sign_product = 1\n\n    for num in arr:\n        sum_magnitudes += abs(num)\n        if num > 0:\n            sign_product *= 1\n        elif num < 0:\n            sign_product *= -1\n        else:\n            sign_product *= 0\n\n    return sum_magnitudes * sign_product\n\n```"}
{"id": "HumanEval/129", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 439, "completion_tokens": 402, "total_tokens": 841, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 439}}, "wall_s": 22.57, "content": "```python\n\nimport heapq\n\ndef minPath(grid, k):\n    n = len(grid)\n    # Directions: up, down, left, right\n    dirs = [(-1, 0), (1, 0), (0, -1), (0, 1)]\n    \n    # For each cell, we store the smallest lexicographic path of length up to k\n    # dp[r][c][l] = list of values for the best path of length l ending at (r,c)\n    # We'll build incrementally.\n    \n    # Initialize dp for length 1: just the cell itself\n    dp = [[[None for _ in range(k+1)] for _ in range(n)] for _ in range(n)]\n    for r in range(n):\n        for c in range(n):\n            dp[r][c][1] = [grid[r][c]]\n    \n    # Build for lengths 2..k\n    for length in range(2, k+1):\n        for r in range(n):\n            for c in range(n):\n                best = None\n                for dr, dc in dirs:\n                    nr, nc = r + dr, c + dc\n                    if 0 <= nr < n and 0 <= nc < n:\n                        prev_path = dp[nr][nc][length-1]\n                        if prev_path is not None:\n                            candidate = prev_path + [grid[r][c]]\n                            if best is None or candidate < best:\n                                best = candidate\n                dp[r][c][length] = best\n    \n    # Find the overall best path of length k\n    overall_best = None\n    for r in range(n):\n        for c in range(n):\n            path = dp[r][c][k]\n            if path is not None:\n                if overall_best is None or path < overall_best:\n                    overall_best = path\n    return overall_best\n\n```"}
{"id": "HumanEval/130", "passed": false, "detail": "Traceback (most recent call last):\n  File \"<string>\", line 39, in <module>\n    check(tri)\n    ~~~~~^^^^^\n  File \"<string>\", line 26, in check\n    assert candidate(3) == [1, 3, 2.0, 8.0]\n           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^\nAssertionError", "finish_reason": "stop", "usage": {"prompt_tokens": 277, "completion_tokens": 166, "total_tokens": 443, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 277}}, "wall_s": 10.09, "content": "Here's the implementation for the Tribonacci sequence as described:\n\n```python\ndef tri(n):\n    def compute_tri(k, memo):\n        if k in memo:\n            return memo[k]\n        if k == 1:\n            memo[k] = 3\n        elif k % 2 == 0:\n            memo[k] = 1 + k // 2\n        else:  # k is odd\n            memo[k] = compute_tri(k - 1, memo) + compute_tri(k - 2, memo) + compute_tri(k + 1, memo)\n        return memo[k]\n    \n    memo = {}\n    result = []\n    for i in range(1, n + 1):\n        result.append(compute_tri(i, memo))\n    return result\n```"}
{"id": "HumanEval/131", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 114, "completion_tokens": 137, "total_tokens": 251, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 114}}, "wall_s": 7.89, "content": "```python\n\ndef digits(n):\n    \"\"\"Given a positive integer n, return the product of the odd digits.\n    Return 0 if all digits are even.\n    For example:\n    digits(1)  == 1\n    digits(4)  == 0\n    digits(235) == 15\n    \"\"\"\n    product = 1\n    found_odd = False\n    while n > 0:\n        digit = n % 10\n        if digit % 2 == 1:\n            product *= digit\n            found_odd = True\n        n //= 10\n    return product if found_odd else 0\n\n```"}
{"id": "HumanEval/132", "passed": false, "detail": "Traceback (most recent call last):\n  File \"<string>\", line 55, in <module>\n    check(is_nested)\n    ~~~~~^^^^^^^^^^^\n  File \"<string>\", line 38, in check\n    assert candidate('[]]]]]]][[[[[]') == False\n           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^\nAssertionError", "finish_reason": "stop", "usage": {"prompt_tokens": 184, "completion_tokens": 282, "total_tokens": 466, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 184}}, "wall_s": 15.25, "content": "Here's the implementation for the function you described:\n\n```python\n\ndef is_nested(string):\n    '''\n    Create a function that takes a string as input which contains only square brackets.\n    The function should return True if and only if there is a valid subsequence of brackets \n    where at least one bracket in the subsequence is nested.\n\n    is_nested('[[]]') \u279e True\n    is_nested('[]]]]]]][[[[[]') \u279e False\n    is_nested('[][]') \u279e False\n    is_nested('[]') \u279e False\n    is_nested('[[][]]') \u279e True\n    is_nested('[[]][[') \u279e True\n    '''\n    # Track the depth of valid bracket subsequences\n    depth = 0\n    max_depth = 0\n    \n    for char in string:\n        if char == '[':\n            depth += 1\n            max_depth = max(max_depth, depth)\n        elif char == ']':\n            if depth > 0:\n                depth -= 1\n    \n    # A valid subsequence with nesting means at least one '[' is matched\n    # with a later ']' while another '[' is opened inside before closing.\n    # This is equivalent to having a maximum depth >= 2 at some point.\n    return max_depth >= 2\n\n```"}
{"id": "HumanEval/133", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 201, "completion_tokens": 197, "total_tokens": 398, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 201}}, "wall_s": 11.11, "content": "Here's the implementation:\n\n```python\nimport math\n\ndef sum_squares(lst):\n    \"\"\"You are given a list of numbers.\n    You need to return the sum of squared numbers in the given list,\n    round each element in the list to the upper int(Ceiling) first.\n    Examples:\n    For lst = [1,2,3] the output should be 14\n    For lst = [1,4,9] the output should be 98\n    For lst = [1,3,5,7] the output should be 84\n    For lst = [1.4,4.2,0] the output should be 29\n    For lst = [-2.4,1,1] the output should be 6\n    \"\"\"\n    total = 0\n    for num in lst:\n        ceil_val = math.ceil(num)\n        total += ceil_val * ceil_val\n    return total\n```"}
{"id": "HumanEval/134", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 187, "completion_tokens": 204, "total_tokens": 391, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 187}}, "wall_s": 11.64, "content": "Here's the implementation for the function:\n\n```python\ndef check_if_last_char_is_a_letter(txt):\n    \"\"\"\n    Returns True if the last character of a given string is an alphabetical character\n    and is not part of a word (i.e., it is a standalone letter separated by spaces),\n    and False otherwise.\n    \"\"\"\n    if not txt or txt[-1] == ' ':\n        return False\n    \n    # Check if the last character is an alphabetical letter\n    if not txt[-1].isalpha():\n        return False\n    \n    # Check if it's part of a word: if there's a preceding character that is not a space,\n    # then it's part of a word.\n    # If the string has length 1, it's a standalone letter.\n    if len(txt) == 1:\n        return True\n    \n    # If the character before the last is a space, then the last char is standalone\n    return txt[-2] == ' '\n```"}
{"id": "HumanEval/135", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 146, "completion_tokens": 152, "total_tokens": 298, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 146}}, "wall_s": 8.64, "content": "```python\ndef can_arrange(arr):\n    \"\"\"Create a function which returns the largest index of an element which\n    is not greater than or equal to the element immediately preceding it. If\n    no such element exists then return -1. The given array will not contain\n    duplicate values.\n\n    Examples:\n    can_arrange([1,2,4,3,5]) = 3\n    can_arrange([1,2,3]) = -1\n    \"\"\"\n    if len(arr) < 2:\n        return -1\n    \n    result = -1\n    for i in range(1, len(arr)):\n        if arr[i] < arr[i-1]:\n            result = i\n    return result\n```"}
{"id": "HumanEval/136", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 189, "completion_tokens": 242, "total_tokens": 431, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 189}}, "wall_s": 13.27, "content": "Here's the implementation for the function you described:\n\n```python\ndef largest_smallest_integers(lst):\n    '''\n    Create a function that returns a tuple (a, b), where 'a' is\n    the largest of negative integers, and 'b' is the smallest\n    of positive integers in a list.\n    If there is no negative or positive integers, return them as None.\n\n    Examples:\n    largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)\n    largest_smallest_integers([]) == (None, None)\n    largest_smallest_integers([0]) == (None, None)\n    '''\n    largest_negative = None\n    smallest_positive = None\n\n    for num in lst:\n        if num < 0:\n            if largest_negative is None or num > largest_negative:\n                largest_negative = num\n        elif num > 0:\n            if smallest_positive is None or num < smallest_positive:\n                smallest_positive = num\n\n    return (largest_negative, smallest_positive)\n```"}
{"id": "HumanEval/137", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 184, "completion_tokens": 277, "total_tokens": 461, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 184}}, "wall_s": 15.16, "content": "Here's the implementation for the function you described:\n\n```python\ndef compare_one(a, b):\n    \"\"\"\n    Create a function that takes integers, floats, or strings representing\n    real numbers, and returns the larger variable in its given variable type.\n    Return None if the values are equal.\n    Note: If a real number is represented as a string, the floating point might be . or ,\n\n    compare_one(1, 2.5) \u279e 2.5\n    compare_one(1, \"2,3\") \u279e \"2,3\"\n    compare_one(\"5,1\", \"6\") \u279e \"6\"\n    compare_one(\"1\", 1) \u279e None\n    \"\"\"\n    def to_number(val):\n        if isinstance(val, (int, float)):\n            return float(val)\n        if isinstance(val, str):\n            # Replace comma with dot for parsing\n            normalized = val.replace(',', '.')\n            return float(normalized)\n        return None\n\n    num_a = to_number(a)\n    num_b = to_number(b)\n\n    if num_a is None or num_b is None:\n        return None\n\n    if abs(num_a - num_b) < 1e-12:\n        return None\n\n    if num_a > num_b:\n        return a\n    else:\n        return b\n```"}
{"id": "HumanEval/138", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 124, "completion_tokens": 177, "total_tokens": 301, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 124}}, "wall_s": 9.79, "content": "Here's the implementation:\n\n```python\ndef is_equal_to_sum_even(n):\n    \"\"\"Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers\n    Example\n    is_equal_to_sum_even(4) == False\n    is_equal_to_sum_even(6) == False\n    is_equal_to_sum_even(8) == True\n    \"\"\"\n    # The smallest sum of 4 positive even numbers is 2+2+2+2 = 8\n    # Any even number >= 8 can be written as sum of 4 positive even numbers\n    # Because we can adjust by adding 2 to one term and subtracting 2 from another\n    # So condition: n must be even and >= 8\n    return n >= 8 and n % 2 == 0\n```"}
{"id": "HumanEval/139", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 138, "completion_tokens": 148, "total_tokens": 286, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 138}}, "wall_s": 8.65, "content": "```python\n\ndef special_factorial(n):\n    \"\"\"The Brazilian factorial is defined as:\n    brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!\n    where n > 0\n\n    For example:\n    >>> special_factorial(4)\n    288\n\n    The function will receive an integer as input and should return the special\n    factorial of this integer.\n    \"\"\"\n    # Compute factorial iteratively and accumulate product\n    result = 1\n    current_factorial = 1\n    for i in range(1, n + 1):\n        current_factorial *= i\n        result *= current_factorial\n    return result\n\n```"}
{"id": "HumanEval/140", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 154, "completion_tokens": 245, "total_tokens": 399, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 154}}, "wall_s": 13.43, "content": "Here's the implementation for the `fix_spaces` function:\n\n```python\ndef fix_spaces(text):\n    \"\"\"\n    Given a string text, replace all spaces in it with underscores, \n    and if a string has more than 2 consecutive spaces, \n    then replace all consecutive spaces with - \n    \n    fix_spaces(\"Example\") == \"Example\"\n    fix_spaces(\"Example 1\") == \"Example_1\"\n    fix_spaces(\" Example 2\") == \"_Example_2\"\n    fix_spaces(\" Example   3\") == \"_Example-3\"\n    \"\"\"\n    result = []\n    i = 0\n    while i < len(text):\n        if text[i] == ' ':\n            # Count consecutive spaces\n            j = i\n            while j < len(text) and text[j] == ' ':\n                j += 1\n            space_count = j - i\n            if space_count > 2:\n                result.append('-')\n            else:\n                for _ in range(space_count):\n                    result.append('_')\n            i = j\n        else:\n            result.append(text[i])\n            i += 1\n    return ''.join(result)\n```"}
{"id": "HumanEval/141", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 260, "completion_tokens": 392, "total_tokens": 652, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 260}}, "wall_s": 21.11, "content": "Here's the implementation for the function you described:\n\n```python\ndef file_name_check(file_name):\n    \"\"\"Create a function which takes a string representing a file's name, and returns\n    'Yes' if the the file's name is valid, and returns 'No' otherwise.\n    A file's name is considered to be valid if and only if all the following conditions \n    are met:\n    - There should not be more than three digits ('0'-'9') in the file's name.\n    - The file's name contains exactly one dot '.'\n    - The substring before the dot should not be empty, and it starts with a letter from \n    the latin alphapet ('a'-'z' and 'A'-'Z').\n    - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n    Examples:\n    file_name_check(\"example.txt\") # => 'Yes'\n    file_name_check(\"1example.dll\") # => 'No' (the name should start with a latin alphapet letter)\n    \"\"\"\n    # Count digits\n    digit_count = sum(1 for ch in file_name if ch.isdigit())\n    if digit_count > 3:\n        return 'No'\n\n    # Check exactly one dot\n    if file_name.count('.') != 1:\n        return 'No'\n\n    # Split into parts\n    parts = file_name.split('.')\n    before_dot = parts[0]\n    after_dot = parts[1]\n\n    # Check before dot is not empty and starts with a letter\n    if not before_dot or not before_dot[0].isalpha():\n        return 'No'\n\n    # Check after dot is one of the allowed extensions\n    if after_dot not in ['txt', 'exe', 'dll']:\n        return 'No'\n\n    return 'Yes'\n```"}
{"id": "HumanEval/142", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 213, "completion_tokens": 240, "total_tokens": 453, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 213}}, "wall_s": 13.5, "content": "Here's the implementation for the function you described:\n\n```python\ndef sum_squares(lst):\n    \"\"\"\n    This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n    multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n    change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n    \n    Examples:\n    For lst = [1,2,3] the output should be 6\n    For lst = []  the output should be 0\n    For lst = [-1,-5,2,-1,-5]  the output should be -126\n    \"\"\"\n    total = 0\n    for i, val in enumerate(lst):\n        if i % 3 == 0:\n            total += val * val\n        elif i % 4 == 0:\n            total += val * val * val\n        else:\n            total += val\n    return total\n```"}
{"id": "HumanEval/143", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 193, "completion_tokens": 101, "total_tokens": 294, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 193}}, "wall_s": 6.65, "content": "Here's the implementation:\n\n```python\ndef words_in_sentence(sentence):\n    def is_prime(n):\n        if n < 2:\n            return False\n        for i in range(2, int(n ** 0.5) + 1):\n            if n % i == 0:\n                return False\n        return True\n\n    words = sentence.split()\n    result_words = [word for word in words if is_prime(len(word))]\n    return \" \".join(result_words)\n```"}
{"id": "HumanEval/144", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 200, "completion_tokens": 207, "total_tokens": 407, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 200}}, "wall_s": 11.82, "content": "Here's the implementation for the `simplify` function:\n\n```python\nfrom fractions import Fraction\n\ndef simplify(x, n):\n    \"\"\"Your task is to implement a function that will simplify the expression\n    x * n. The function returns True if x * n evaluates to a whole number and False\n    otherwise. Both x and n, are string representation of a fraction, and have the following format,\n    <numerator>/<denominator> where both numerator and denominator are positive whole numbers.\n\n    You can assume that x, and n are valid fractions, and do not have zero as denominator.\n\n    simplify(\"1/5\", \"5/1\") = True\n    simplify(\"1/6\", \"2/1\") = False\n    simplify(\"7/10\", \"10/2\") = False\n    \"\"\"\n    frac_x = Fraction(x)\n    frac_n = Fraction(n)\n    product = frac_x * frac_n\n    return product.denominator == 1\n```"}
{"id": "HumanEval/145", "passed": false, "detail": "Traceback (most recent call last):\n  File \"<string>\", line 31, in <module>\n    check(order_by_points)\n    ~~~~~^^^^^^^^^^^^^^^^^\n  File \"<string>\", line 20, in check\n    assert candidate([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]\n           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^\nAssertionError", "finish_reason": "stop", "usage": {"prompt_tokens": 158, "completion_tokens": 127, "total_tokens": 285, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 158}}, "wall_s": 7.75, "content": "Here's the implementation for the function you described:\n\n```python\ndef order_by_points(nums):\n    def digit_sum(n):\n        return sum(int(d) for d in str(abs(n)))\n\n    # Create list of (digit_sum, original_index, value) tuples\n    decorated = [(digit_sum(nums[i]), i, nums[i]) for i in range(len(nums))]\n    \n    # Sort by digit_sum first, then by original index\n    decorated.sort(key=lambda x: (x[0], x[1]))\n    \n    # Extract values in sorted order\n    return [x[2] for x in decorated]\n```"}
{"id": "HumanEval/146", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 162, "completion_tokens": 128, "total_tokens": 290, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 162}}, "wall_s": 7.76, "content": "```python\n\ndef specialFilter(nums):\n    \"\"\"\n    Returns the count of numbers in the list that are greater than 10 and\n    whose first and last digits are odd.\n    \"\"\"\n    count = 0\n    for num in nums:\n        if num > 10:\n            # Convert to positive string to handle negative numbers\n            s = str(abs(num))\n            first_digit = int(s[0])\n            last_digit = int(s[-1])\n            if first_digit % 2 == 1 and last_digit % 2 == 1:\n                count += 1\n    return count\n\n```"}
{"id": "HumanEval/147", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 210, "completion_tokens": 847, "total_tokens": 1057, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 210}}, "wall_s": 43.5, "content": "We need to compute the number of triples (i, j, k) with i < j < k such that the sum of the three values a[i] + a[j] + a[k] is divisible by 3, where a[i] = i*i - i + 1.\n\nFirst, let\u2019s analyze the expression modulo 3:\n\nFor i mod 3:\n- If i \u2261 0 (mod 3):  \n  i\u00b2 \u2261 0, -i \u2261 0, so a[i] \u2261 1 (mod 3)\n- If i \u2261 1 (mod 3):  \n  i\u00b2 \u2261 1, -i \u2261 -1 \u2261 2, so a[i] \u2261 1 + 2 + 1 \u2261 4 \u2261 1 (mod 3)\n- If i \u2261 2 (mod 3):  \n  i\u00b2 \u2261 4 \u2261 1, -i \u2261 -2 \u2261 1, so a[i] \u2261 1 + 1 + 1 \u2261 3 \u2261 0 (mod 3)\n\nSo:\n- i \u2261 0 or 1 mod 3 \u2192 a[i] \u2261 1 mod 3\n- i \u2261 2 mod 3 \u2192 a[i] \u2261 0 mod 3\n\nWe want triples where sum \u2261 0 mod 3.  \nLet\u2019s count how many indices fall into each residue class for a given n.\n\nLet:\n- c0 = number of i in [1..n] with i \u2261 0 mod 3 \u2192 floor(n/3)\n- c1 = number with i \u2261 1 mod 3 \u2192 ceil(n/3) or (n+2)//3\n- c2 = number with i \u2261 2 mod 3 \u2192 floor((n+1)/3)\n\nBut careful: i starts at 1, so:\n- i \u2261 1 mod 3: indices 1, 4, 7, ... \u2192 count = (n+2)//3\n- i \u2261 2 mod 3: indices 2, 5, 8, ... \u2192 count = (n+1)//3\n- i \u2261 0 mod 3: indices 3, 6, 9, ... \u2192 count = n//3\n\nNow a[i] mod 3:\n- i \u2261 0 or 1 \u2192 a \u2261 1\n- i \u2261 2 \u2192 a \u2261 0\n\nSo we have two groups:\n- Group A (a \u2261 1): count = c0 + c1\n- Group B (a \u2261 0): count = c2\n\nWe need triples (i<j<k) with sum \u2261 0 mod 3.  \nPossible combinations of residues (1,1,1) \u2192 sum \u2261 0 mod 3? 1+1+1=3 \u2261 0 \u2192 yes.  \n(1,1,0) \u2192 2 mod 3 \u2192 no.  \n(1,0,0) \u2192 1 mod 3 \u2192 no.  \n(0,0,0) \u2192 0 mod 3 \u2192 yes.\n\nSo only triples where all three are from group A, or all three from group B.\n\nNumber of triples from group A: choose 3 from countA = c0+c1.  \nNumber from group B: choose 3 from countB = c2.\n\nTotal = C(countA, 3) + C(countB, 3).\n\nWe can compute using integer arithmetic.\n\nLet\u2019s implement:\n\n```python\ndef get_max_triples(n):\n    c0 = n // 3\n    c1 = (n + 2) // 3\n    c2 = (n + 1) // 3\n    countA = c0 + c1\n    countB = c2\n    \n    def choose3(x):\n        if x < 3:\n            return 0\n        return x * (x-1) * (x-2) // 6\n    \n    return choose3(countA) + choose3(countB)\n```"}
{"id": "HumanEval/148", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 256, "completion_tokens": 144, "total_tokens": 400, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 256}}, "wall_s": 9.01, "content": "Here's the implementation:\n\n```python\ndef bf(planet1, planet2):\n    planets = [\"Mercury\", \"Venus\", \"Earth\", \"Mars\", \"Jupiter\", \"Saturn\", \"Uranus\", \"Neptune\"]\n    \n    if planet1 not in planets or planet2 not in planets:\n        return ()\n    \n    idx1 = planets.index(planet1)\n    idx2 = planets.index(planet2)\n    \n    if idx1 < idx2:\n        start = idx1 + 1\n        end = idx2\n    else:\n        start = idx2 + 1\n        end = idx1\n    \n    return tuple(planets[start:end])\n```"}
{"id": "HumanEval/149", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 231, "completion_tokens": 122, "total_tokens": 353, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 231}}, "wall_s": 7.78, "content": "Here's the implementation for the function you described:\n\n```python\ndef sorted_list_sum(lst):\n    \"\"\"\n    Removes strings with odd lengths from the list, then sorts the remaining\n    strings first by length (ascending) and then alphabetically.\n    \"\"\"\n    # Filter out strings with odd lengths\n    even_length_strings = [s for s in lst if len(s) % 2 == 0]\n    \n    # Sort by length first, then alphabetically\n    even_length_strings.sort(key=lambda x: (len(x), x))\n    \n    return even_length_strings\n```"}
{"id": "HumanEval/150", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 129, "completion_tokens": 137, "total_tokens": 266, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 129}}, "wall_s": 8.03, "content": "Here's the implementation:\n\n```python\ndef x_or_y(n, x, y):\n    \"\"\"A simple program which should return the value of x if n is \n    a prime number and should return the value of y otherwise.\n\n    Examples:\n    for x_or_y(7, 34, 12) == 34\n    for x_or_y(15, 8, 5) == 5\n    \n    \"\"\"\n    if n < 2:\n        return y\n    for i in range(2, int(n ** 0.5) + 1):\n        if n % i == 0:\n            return y\n    return x\n```"}
{"id": "HumanEval/151", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 187, "completion_tokens": 186, "total_tokens": 373, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 187}}, "wall_s": 10.7, "content": "```python\n\ndef double_the_difference(lst):\n    '''\n    Given a list of numbers, return the sum of squares of the numbers\n    in the list that are odd. Ignore numbers that are negative or not integers.\n    \n    double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10\n    double_the_difference([-1, -2, 0]) == 0\n    double_the_difference([9, -2]) == 81\n    double_the_difference([0]) == 0  \n   \n    If the input list is empty, return 0.\n    '''\n    total = 0\n    for num in lst:\n        if isinstance(num, int) and num >= 0 and num % 2 == 1:\n            total += num * num\n    return total\n\n```"}
{"id": "HumanEval/152", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 273, "completion_tokens": 283, "total_tokens": 556, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 273}}, "wall_s": 15.98, "content": "Here's the implementation for the function you described:\n\n```python\ndef compare(game, guess):\n    \"\"\"I think we all remember that feeling when the result of some long-awaited\n    event is finally known. The feelings and thoughts you have at that moment are\n    definitely worth noting down and comparing.\n    Your task is to determine if a person correctly guessed the results of a number of matches.\n    You are given two arrays of scores and guesses of equal length, where each index shows a match. \n    Return an array of the same length denoting how far off each guess was. If they have guessed correctly,\n    the value is 0, and if not, the value is the absolute difference between the guess and the score.\n    \n    \n    example:\n\n    compare([1,2,3,4,5,1],[1,2,3,4,2,-2]) -> [0,0,0,0,3,3]\n    compare([0,5,0,0,0,4],[4,1,1,0,0,-2]) -> [4,4,1,0,0,6]\n    \"\"\"\n    result = []\n    for i in range(len(game)):\n        if game[i] == guess[i]:\n            result.append(0)\n        else:\n            result.append(abs(game[i] - guess[i]))\n    return result\n```"}
{"id": "HumanEval/153", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 318, "completion_tokens": 133, "total_tokens": 451, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 318}}, "wall_s": 8.7, "content": "Here's the implementation for the function you described:\n\n```python\ndef Strongest_Extension(class_name, extensions):\n    def strength(ext):\n        cap = sum(1 for c in ext if c.isupper())\n        sm = sum(1 for c in ext if c.islower())\n        return cap - sm\n\n    strongest_ext = None\n    strongest_strength = None\n\n    for ext in extensions:\n        s = strength(ext)\n        if strongest_ext is None or s > strongest_strength:\n            strongest_ext = ext\n            strongest_strength = s\n\n    return f\"{class_name}.{strongest_ext}\"\n```"}
{"id": "HumanEval/154", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 179, "completion_tokens": 199, "total_tokens": 378, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 179}}, "wall_s": 11.23, "content": "Here's the implementation for the function you described:\n\n```python\ndef cycpattern_check(a, b):\n    \"\"\"You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word\n    cycpattern_check(\"abcd\",\"abd\") => False\n    cycpattern_check(\"hello\",\"ell\") => True\n    cycpattern_check(\"whassup\",\"psus\") => False\n    cycpattern_check(\"abab\",\"baa\") => True\n    cycpattern_check(\"efef\",\"eeff\") => False\n    cycpattern_check(\"himenss\",\"simen\") => True\n    \"\"\"\n    if not b:\n        return False\n    n = len(b)\n    # Generate all rotations of b\n    for i in range(n):\n        rotated = b[i:] + b[:i]\n        if rotated in a:\n            return True\n    return False\n```"}
{"id": "HumanEval/155", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 111, "completion_tokens": 137, "total_tokens": 248, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 111}}, "wall_s": 7.9, "content": "Here's the implementation:\n\n```python\ndef even_odd_count(num):\n    \"\"\"Given an integer. return a tuple that has the number of even and odd digits respectively.\n\n     Example:\n        even_odd_count(-12) ==> (1, 1)\n        even_odd_count(123) ==> (1, 2)\n    \"\"\"\n    num = abs(num)\n    even_count = 0\n    odd_count = 0\n    for digit in str(num):\n        if int(digit) % 2 == 0:\n            even_count += 1\n        else:\n            odd_count += 1\n    return (even_count, odd_count)\n```"}
{"id": "HumanEval/156", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 148, "completion_tokens": 267, "total_tokens": 415, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 148}}, "wall_s": 14.61, "content": "\n```python\n\ndef int_to_mini_roman(number):\n    \"\"\"\n    Given a positive integer, obtain its roman numeral equivalent as a string,\n    and return it in lowercase.\n    Restrictions: 1 <= num <= 1000\n\n    Examples:\n    >>> int_to_mini_roman(19) == 'xix'\n    >>> int_to_mini_roman(152) == 'clii'\n    >>> int_to_mini_roman(426) == 'cdxxvi'\n    \"\"\"\n    # Mapping of values to roman numeral symbols (uppercase for clarity, then lowercased)\n    val_to_roman = [\n        (1000, 'M'),\n        (900, 'CM'),\n        (500, 'D'),\n        (400, 'CD'),\n        (100, 'C'),\n        (90, 'XC'),\n        (50, 'L'),\n        (40, 'XL'),\n        (10, 'X'),\n        (9, 'IX'),\n        (5, 'V'),\n        (4, 'IV'),\n        (1, 'I')\n    ]\n    \n    result = ''\n    num = number\n    for value, symbol in val_to_roman:\n        while num >= value:\n            result += symbol\n            num -= value\n    return result.lower()\n\n```"}
{"id": "HumanEval/157", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 156, "completion_tokens": 159, "total_tokens": 315, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 156}}, "wall_s": 9.27, "content": "```python\n\ndef right_angle_triangle(a, b, c):\n    '''\n    Given the lengths of the three sides of a triangle. Return True if the three\n    sides form a right-angled triangle, False otherwise.\n    A right-angled triangle is a triangle in which one angle is right angle or \n    90 degree.\n    Example:\n    right_angle_triangle(3, 4, 5) == True\n    right_angle_triangle(1, 2, 3) == False\n    '''\n    sides = sorted([a, b, c])\n    # Check triangle inequality and Pythagorean theorem\n    return sides[0] > 0 and sides[0]**2 + sides[1]**2 == sides[2]**2\n\n```"}
{"id": "HumanEval/158", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 164, "completion_tokens": 118, "total_tokens": 282, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 164}}, "wall_s": 7.41, "content": "\n```python\n\ndef find_max(words):\n    \"\"\"\n    Returns the word with the maximum number of unique characters.\n    If multiple words have the same maximum, returns the lexicographically smallest.\n    \"\"\"\n    best_word = None\n    best_unique_count = -1\n\n    for word in words:\n        unique_count = len(set(word))\n        if unique_count > best_unique_count:\n            best_unique_count = unique_count\n            best_word = word\n        elif unique_count == best_unique_count and word < best_word:\n            best_word = word\n\n    return best_word\n\n```"}
{"id": "HumanEval/159", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 320, "completion_tokens": 313, "total_tokens": 633, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 320}}, "wall_s": 17.58, "content": "```python\n\ndef eat(number, need, remaining):\n    \"\"\"\n    You're a hungry rabbit, and you already have eaten a certain number of carrots,\n    but now you need to eat more carrots to complete the day's meals.\n    you should return an array of [ total number of eaten carrots after your meals,\n                                    the number of carrots left after your meals ]\n    if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n    \n    Example:\n    * eat(5, 6, 10) -> [11, 4]\n    * eat(4, 8, 9) -> [12, 1]\n    * eat(1, 10, 10) -> [11, 0]\n    * eat(2, 11, 5) -> [7, 0]\n    \n    Variables:\n    @number : integer\n        the number of carrots that you have eaten.\n    @need : integer\n        the number of carrots that you need to eat.\n    @remaining : integer\n        the number of remaining carrots thet exist in stock\n    \n    Constrain:\n    * 0 <= number <= 1000\n    * 0 <= need <= 1000\n    * 0 <= remaining <= 1000\n\n    Have fun :)\n    \"\"\"\n    eaten = min(need, remaining)\n    total_eaten = number + eaten\n    remaining_after = remaining - eaten\n    return [total_eaten, remaining_after]\n\n```"}
{"id": "HumanEval/160", "passed": false, "detail": "Traceback (most recent call last):\n  File \"<string>\", line 59, in <module>\n    check(do_algebra)\n    ~~~~~^^^^^^^^^^^^\n  File \"<string>\", line 52, in check\n    assert candidate(['+', '*', '-'], [2, 3, 4, 5]) == 9\n           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^\nAssertionError", "finish_reason": "stop", "usage": {"prompt_tokens": 250, "completion_tokens": 341, "total_tokens": 591, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 250}}, "wall_s": 18.53, "content": "Here's the implementation for the function you described:\n\n```python\ndef do_algebra(operator, operand):\n    \"\"\"\n    Given two lists operator, and operand. The first list has basic algebra operations, and \n    the second list is a list of integers. Use the two given lists to build the algebric \n    expression and return the evaluation of this expression.\n\n    The basic algebra operations:\n    Addition ( + ) \n    Subtraction ( - ) \n    Multiplication ( * ) \n    Floor division ( // ) \n    Exponentiation ( ** ) \n\n    Example:\n    operator['+', '*', '-']\n    array = [2, 3, 4, 5]\n    result = 2 + 3 * 4 - 5\n    => result = 9\n\n    Note:\n        The length of operator list is equal to the length of operand list minus one.\n        Operand is a list of of non-negative integers.\n        Operator list has at least one operator, and operand list has at least two operands.\n\n    \"\"\"\n    # Start with the first operand\n    result = operand[0]\n    \n    # Apply each operator to the running result and the next operand\n    for i, op in enumerate(operator):\n        next_val = operand[i + 1]\n        if op == '+':\n            result = result + next_val\n        elif op == '-':\n            result = result - next_val\n        elif op == '*':\n            result = result * next_val\n        elif op == '//':\n            result = result // next_val\n        elif op == '**':\n            result = result ** next_val\n    \n    return result\n```"}
{"id": "HumanEval/161", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 150, "completion_tokens": 90, "total_tokens": 240, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 150}}, "wall_s": 5.94, "content": "\n```python\n\ndef solve(s):\n    result = []\n    has_letter = False\n    for ch in s:\n        if ch.isalpha():\n            has_letter = True\n            if ch.islower():\n                result.append(ch.upper())\n            else:\n                result.append(ch.lower())\n        else:\n            result.append(ch)\n    if not has_letter:\n        return ''.join(reversed(result))\n    return ''.join(result)\n\n```"}
{"id": "HumanEval/162", "passed": true, "detail": "ok", "finish_reason": "stop", "usage": {"prompt_tokens": 121, "completion_tokens": 105, "total_tokens": 226, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 121}}, "wall_s": 6.39, "content": "```python\nimport hashlib\n\ndef string_to_md5(text):\n    \"\"\"\n    Given a string 'text', return its md5 hash equivalent string.\n    If 'text' is an empty string, return None.\n\n    >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'\n    \"\"\"\n    if text == \"\":\n        return None\n    return hashlib.md5(text.encode()).hexdigest()\n```"}
{"id": "HumanEval/163", "passed": false, "detail": "Traceback (most recent call last):\n  File \"<string>\", line 34, in <module>\n    check(generate_integers)\n    ~~~~~^^^^^^^^^^^^^^^^^^^\n  File \"<string>\", line 25, in check\n    assert candidate(2, 10) == [2, 4, 6, 8], \"Test 1\"\n           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^\nAssertionError: Test 1", "finish_reason": "stop", "usage": {"prompt_tokens": 151, "completion_tokens": 158, "total_tokens": 309, "prompt_tokens_details": {"cached_tokens": 0, "cache_write_tokens": 151}}, "wall_s": 9.16, "content": "```python\ndef generate_integers(a, b):\n    \"\"\"\n    Given two positive integers a and b, return the even digits between a\n    and b, in ascending order.\n\n    For example:\n    generate_integers(2, 8) => [2, 4, 6, 8]\n    generate_integers(8, 2) => [2, 4, 6, 8]\n    generate_integers(10, 14) => []\n    \"\"\"\n    low = min(a, b)\n    high = max(a, b)\n    result = []\n    for num in range(low, high + 1):\n        if num % 2 == 0:\n            result.append(num)\n    return result\n```"}
